How to set path of a config.ini file in a Runnable Jar?

Question

i'm doing a program in java, that will be exported in a runnable JAR and executed in windows as service using YAJSW, i have to read a config.ini file that have important params for the execution, but i'm setting a fixed path:

Path configFile = Paths.get("D:\\Folder\\config.ini");

The problem is that i don't know the path where it will be executed on final user pc. i tried this:

Path txtParametro = Paths.get("\\config.ini");

because the .ini file will be in the same folder of .jar, but didn't work.

Someone has any idea of how i can handle this?

I thought of environment variables ... but would have to manually do it, is not an option.

you need to find out the directory of the jar file :) probably from system property `java.class.path` — ZhongYu, Jun 08 '15 at 17:25

score 1 · Answer 1 · answered Jun 08 '15 at 17:59

You can set the file to be created in a specific location so that the program will always know where it will be:

File file = new File("D:\\Folder\\config.ini");
if (!file.exists()){
    file.createNewFile();
}

Regards, Thomas

score 0 · Answer 2 · edited May 23 '17 at 10:28

0

If the file is part of the JAR then you could load it like this:

Class.getResourceAsStream("config.ini");

As described here:

How do I access a config file inside the jar?

If not in A JAR please let us know.

edited May 23 '17 at 10:28

Community

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answered Jun 08 '15 at 17:55

Jeremy

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score 0 · Answer 3 · answered Jun 08 '15 at 18:58

Found a solution, that way:

assuming that config.ini is in the same folder of .jar

File pathJAR = new File(Main.class.getProtectionDomain().getCodeSource().getLocation().toURI());

it returns me the path of running jar, "D:\Folder\name.jar", then i replaces "name.jar" by "config.ini".

not so beatiful, but works.

How to set path of a config.ini file in a Runnable Jar?

3 Answers3