This is the interrupt I use to input a number, however it does not allow me to input numbers greater than 9:
mov AH, 08h
int 21h
Is there a different interrupt which will allow me to input a 2-digit number as well?
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Thing is, I intend to use the number later on. I don't want it to be divided into digits and prinited out afterwards. – Jun 09 '15 at 16:47
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Capture the number as string, then convert it to number. To display a number, convert it to string, here are the procs you need = https://stackoverflow.com/questions/30243848/assembly-x86-date-to-number-breaking-a-string-into-smaller-sections/30244131#30244131 . With this answer you can input bigger numbers. – Jose Manuel Abarca Rodríguez Jun 09 '15 at 16:48
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And String input is AH = 09h, right? – Jun 09 '15 at 16:49
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09 is output (printf), 0A is input (scanf). – Jose Manuel Abarca Rodríguez Jun 09 '15 at 16:49
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A simpler example = http://stackoverflow.com/questions/30724177/8086-assembly-arrays-with-i-o/30736531#30736531 – Jose Manuel Abarca Rodríguez Jun 09 '15 at 16:55
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With 08h you are requesting a single character input, see documentation e.g. here or a tutorial here. Reading two digits will then take two int 21hs. Alternatively, you may take a look at using 0ah buffered input, but considering it's only two characters:
mov ah, 08h
int 21h
mov dl, al
int 21h
; now dl contains the first character, al the second
Jens
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It's not how hardware works. But as Jose points out in his comment, you can write yourself a helper function which wraps multi-character input for you. – Jens Jun 09 '15 at 16:49
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1@Steven1903 There's away to read an entire line. There's also away to read a certain number of characters, but when that number of characters is two, you might as well do what Jens suggests. – Ross Ridge Jun 09 '15 at 16:50
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