2

I'm working on a project involving sharing to Pinterest, but I'd prefer not to use their JS library. I expected to just need a link like "https://www.pinterest.com/pin/create/button/?url=https%3A%2F%2Fwww.google.com%2Fimages%2Fsrpr%2Flogo11w.png", but I'm getting an error stating "Parameter 'image_url' (value http:null) is not a valid URL format." What am I doing wrong here?

vpzomtrrfrt
  • 483
  • 6
  • 16
  • were you able to find a fix for it? – Alfie Jun 26 '15 at 15:07
  • I ended up trying again and specifying the image as `media` and the page as `url` and it seemed to work, though I'm not sure why. – vpzomtrrfrt Jun 26 '15 at 15:40
  • Good thoughts over here: http://stackoverflow.com/questions/10690019/link-to-pin-it-on-pinterest-without-generating-a-button – sheriffderek Jun 27 '15 at 03:49
  • I had it working without the `media` arg (it would look at `og:image` at the source url) but it seems to have regressed and now I need to put in a `media` arg or else I get the mentioned error. – Tim Tisdall May 24 '16 at 15:20

1 Answers1

0

i'm faced the same problem and solved changing image_url for img_url

Rafael Gomes
  • 1
  • Your answer could be improved with additional supporting information. Please [edit] to add further details, such as citations or documentation, so that others can confirm that your answer is correct. You can find more information on how to write good answers [in the help center](/help/how-to-answer). – Community Oct 28 '22 at 08:08