Code Golf: ASCII Art number

Question

Possible Duplicate:
Code Golf - Banner Generation

Post your shortest code to convert a number into a ASCII art digits.

Input - Assume that an integer variable called z has already been set containing the number.

Output - Print the output to the console.

Quality - The lower number of characters, the better.

Formatting - Flexible, providing it is ASCII art and looks like a number. There must also be some spacing between digits.

Test input: 365

GGGGGGGGGGG....GGGGGGGGGGGG...GGGGGGGGGGG
..........G....G..............G..........
..........G....G..............G..........
..GGGGGGGGG....GGGGGGGGGGGG...GGGGGGGGGGG
..........G....G..........G.............G
..........G....G..........G.............G
GGGGGGGGGGG....GGGGGGGGGGGG...GGGGGGGGGGG

Please read http://meta.stackexchange.com/questions/24242/acceptable-level-of-code-golf-questions. Not a bad code golf, just needs a little more specification. — Chris Lutz, Jun 19 '10 at 23:50
You should probably also add how each number is represented in this `7x11` matrix. Also things like spacing between each character - should there be 3 spaces between each printed digit? Are those dots only to indicate space, or must be part of the output? — Anurag, Jun 20 '10 at 00:01
Very similar to a [recent code-golf](http://stackoverflow.com/questions/2985540/code-golf-banner-generation). — , Jun 20 '10 at 00:07

score 4 · Answer 1 · edited Jun 20 '10 at 04:39

4

Python: 173 characters

for i in range(5):
    a=""
    for j in str(z):
        y=int("03330222220201002020330220102001030022220303003020"[int(j)*5+i])*8
        a+="."+("#"*9+"."*14+"##"+"."*6+"#")[y:y+8]
    print a

edited Jun 20 '10 at 04:39

Nas Banov

28,347
6
48
67

answered Jun 19 '10 at 23:48

Gelatin

2,393
1
24
29

please note you need to count new lines as well. it's 168 chars with identation but w/o new lines. Need to add +5 for \n = 173 – Nas Banov Jun 20 '10 at 02:42
I don't have Python installed on this machine so I'll take your word for it that this works, somehow. There is a voice in the back of my head telling me that you can somehow reduce your character count using a list comprehension, but of course, I may be totally wrong. – Tyler Jun 21 '10 at 05:54

score 1 · Answer 2 · answered Jun 20 '10 at 00:00

1

Bash: 9 characters

figlet $z

;)

answered Jun 20 '10 at 00:00

MiffTheFox

21,302
14
69
94

2

ewwww... this is not solution in bash but in figlet.pls no trivialisms! – Nas Banov Jun 20 '10 at 02:35
@EnTrr - When I got here the question was at -1 with a vote to close, I figured it was going to be closed soon and I shouldn't take it so seriously... ;) – MiffTheFox Jun 20 '10 at 03:28

score 1 · Answer 3 · answered Jun 21 '10 at 05:26

Ruby - 139 chars

(0..4).map{|i|puts z.to_s.chars.map{|j|(?#*9+?.*14+'##'+?.*6+?#)[(?0+"ubp9x453o9jzme0cs08".to_i(36).to_s(4))[j.to_i*5+i].to_i*8,8]+' '}*''}

Output for z = 365

> asciinum.rb
######## ######## ########
.......# #....... #.......
######## ######## ########
.......# #......# .......#
######## ######## ########

Code Golf: ASCII Art number

3 Answers3

Ruby - 139 chars

Linked