Sorted list python

Asked Jun 11 '15 at 12:54

Active Jun 11 '15 at 13:17

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I'm trying to sort a list of string in python. This list is composed of name of files like 1.svg 2.svg ... The problem is when I work with 10.svg the list become : 1.svg 10.svg 2.svg and I need 1.svg 2.svg 10.svg Do you know how to do that ?

Thanks,

I saw the duplicate link but I can't import natsort, maybe it needs python 3.0 no ? (I'm am working with 2.7)

edited Jun 11 '15 at 13:17

asked Jun 11 '15 at 12:54

Milodupipo

So you're trying to sort the strings as if the first part were an integer? – Alecg_O Jun 11 '15 at 13:16
Another option if you can't get nartsort: – Alecg_O Jun 11 '15 at 13:35
x = [str(item) + '.svg' for item in sorted([int(item.split('.')[0]) for item in x])] – Alecg_O Jun 11 '15 at 13:35
ValueError: invalid literal for int() with base 10: '/path/svg/1' – Milodupipo Jun 11 '15 at 13:44
a = ['1.svg', '2.svg', '3.svg', '10.svg'] a.sort(key=lambda x: int(x.split('.')[0])) – rajeshv90 Jun 11 '15 at 16:04

Sorted list python

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