count elements consecutive array php

Question

I have the array:

$type = ['A','A','A','E','E','E','A','E','A','A','E','E'];
          1   2   3                       4   5

And I intend to count the number of elements A that are included in consecutive chains with length more or equal 2. In the example I have three chains but i want count only two of them. Altogether result should be 5.

Try this = http://stackoverflow.com/questions/6300833/searching-for-consecutive-values-in-an-array — Jose Manuel Abarca Rodríguez, Jun 12 '15 at 15:34
Or this one = http://stackoverflow.com/questions/28614124/php-number-of-consecutive-elements-in-array — Jose Manuel Abarca Rodríguez, Jun 12 '15 at 15:41
@Rizier123 unhold this question. I've edited it. But reputation is not enough :) — splash58, Jun 12 '15 at 19:18

splash58 · Accepted Answer · 2015-06-12T17:07:55.010

Find consecutive chains of 'CA"

$count = 0;
$link = array();                     // Here will be chain lengths

array_push($types, '');              // to work if the last item == 'CA'

foreach($types as $item) 
  if ($item == 'CA') $count++;       
  else if ($count) 
         { $link[] = $count; $count = 0; }  

rsort($link);                        // 3, 2, 1
$sum = 0;
foreach ($link as $i) 
   if ($i >= 2) $sum += $i;          // Count result
   else break;                       // Further chains are shorter than we want

echo $sum;

count elements consecutive array php

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