Enter single digit number as input. the output will be converted to words and if the input is 0, the program will exit

Question

Example: Enter a single digit number:2 You have entered number Two Enter a single digit number:4 You have entered number Four Enter a single digit number:0 You have entered number Zero the program will exit/quit..

Answer 1

Take a look at the switch-case statement here.

Something like:

switch(input){

  case 0: return;
  case 1: //do each case separately.
  case 2: // or
  default://do something here if you want to parse any number to text.
}

UPDATE: There is an answer to parse numbers into words here.

Answer 2

import java.util.Scanner;
public class GetInputFromUser{
    public static void main(String args[]){
      Scanner in = new Scanner(System.in);
        System.out.print("Enter a number:");
          int s = in.nextInt();
  System.out.println("You entered number "+s);
}

}

Answer 3

You can use bellow code for your desire input output:

    Scanner conin=new Scanner(System.in);
    System.out.println("Enter single digit number:");
      String[] array = {"exit/quit","one", "two", "three","four","five","six","seven","eight","nine"};
    int a=conin.nextInt();
    if(a<10){
     while (a!=0) {            
      System.out.println("You have entered number:"+array[a]);
      a=conin.nextInt();

    }
   System.out.println("Program "+array[a]);
   System.exit(0);   
    }else{
        System.out.println("not allow"); 
        System.exit(0);
    }