How to extract the relative url from the absolute url in Java

Question

I have this website:

https://asd.com/somestuff/another.html

and I want to extract the relative part out of it:

somestuff/another.html

How do I do that?

EDIT: I was offered an answer to a question, but the problem there was to build the absolute url out of the relative which is not what I'm interested in.

possible duplicate of [Building an absolute URL from a relative URL in Java](http://stackoverflow.com/questions/1389184/building-an-absolute-url-from-a-relative-url-in-java) — CoderNeji, Jun 15 '15 at 11:29
Sorry my mistake... Find your answer here http://www.java2s.com/Code/Java/Network-Protocol/ResolvearelativeURLstringagainstanabsoluteURLstring.htm — CoderNeji, Jun 15 '15 at 11:32
@J.K. According to your new edit. Where are you going to trying to retrieve the absolute path if it is not from your relative website? — Francisco Romero, Jun 15 '15 at 11:36

score 9 · Accepted Answer · edited May 23 '17 at 12:17

You could use the getPath() method of the URL object:

URL url = new URL("https://asd.com/somestuff/another.html");
System.out.println(url.getPath());  // prints "/somestuff/another.html"

Now, this only brings the actual path. If you need more information (the anchor or the parameters passed as get values), you need to call other accessors of the URL object:

URL url = new URL("https://asd.com/somestuff/another.html?param=value#anchor");
System.out.println(url.getPath());  // prints "/somestuff/another.html"
System.out.println(url.getQuery()); // prints "param=value"
System.out.println(url.getRef());   // prints "anchor"

A possible use to generate the relative URL without much code, based on Hiru's answer:

URL absolute = new URL(url, "/");
String relative = url.toString().substring(absolute.toString().length());
System.out.println(relative); // prints "somestuff/another.html?param=value#anchor"

very brief description!! +1 @Chop – Hiren Jun 15 '15 at 12:05 — Hiren, Jun 15 '15 at 12:05

score 2 · Answer 2 · answered Jun 15 '15 at 11:32

2

if you know that the domain will always be .com then you can try something like this:

String url = "https://asd.com/somestuff/another.html";
String[] parts = url.split(".com/");
//parts[1] is the string after the .com/

answered Jun 15 '15 at 11:32

Nagarz

178
2
13

2

it would be .com specific.. what if its "https://asd.in/somestuff/another.html" or something else – Hiren Jun 15 '15 at 11:36
@Hiru This response assumes that `url` contains "XXX.com". – Stephan Apr 02 '18 at 08:23

score 1 · Answer 3 · answered Jun 15 '15 at 11:43

1

The URL consists of the following elements (note that some optional elements are omitted): 1) scheme 2) hostname 3) [port] 4) path 5) query 6) fragment Using the Java URL API, you can do the following:

URL u = new URL("https://randomsite.org/another/randomPage.html");
System.out.println(u.getPath());

Edit#1 Seeing Chop's answer, in case you have query elements in your URL, such as

?name=foo&value=bar

Using the getQuery() method will not return the resource path, just the query part.

answered Jun 15 '15 at 11:43

Aleksander Panayotov

145
1
6

Yep, I was mistaken and made a test to make sure I was not giving bad advice. I also included more details about `getQuery()` and `getRef()` before seeing your answer. Great minds think alike. :) – Chop Jun 15 '15 at 11:49

Hiren · Answer 4 · 2015-06-15T11:56:04.623

1

Try This

Use it Globally not only for .com

    URL u=new URL("https://asd.in/somestuff/another.html");
    String u1=new URL(u, "/").toString();
    String u2=u.toString();
    String[] u3=u2.split(u1);
    System.out.println(u3[1]); //it prints:   somestuff/another.html

edited Jun 15 '15 at 11:56

answered Jun 15 '15 at 11:44

Hiren

1,427
1
18
35

score 1 · Answer 5 · answered Jun 15 '15 at 11:51

You can do this using below snippet.

 String str="https://asd.org/somestuff/another.html";
    if(str.contains("//")) //To remove any protocol specific header.
    {
        str=str.split("//")[1];
    }
    System.out.println(str.substring(str.indexOf("/")+1)); // taking the first '/'

score 0 · Answer 6 · answered Jun 05 '20 at 08:41

My solution based on java.net.URI

URI _absoluteURL = new URI(absoluteUrl).normalize();
String root = _absoluteURL.getScheme() + "://" + _absoluteURL.getAuthority();
URI relative = new URI(root).relativize(_absoluteURL);

String result = relative.toString();

score 0 · Answer 7 · answered May 02 '22 at 12:41

Consider using Apache Commons VFS...

import org.apache.commons.vfs2.FileSystemException;
import org.apache.commons.vfs2.VFS;
import org.apache.commons.vfs2.impl.StandardFileSystemManager;

import java.net.URI;
import java.net.URISyntaxException;
import java.net.URL;
import java.net.URLStreamHandlerFactory;

public class StudyURI {
    public static void main(String[] args) throws URISyntaxException, FileSystemException {
        StandardFileSystemManager fileSystemManager = (StandardFileSystemManager) VFS.getManager();
        URLStreamHandlerFactory factory = fileSystemManager.getURLStreamHandlerFactory();
        URL.setURLStreamHandlerFactory(factory);

        URI baseURI = fileSystemManager.resolveFile("https://asd.com/").getURI();
        URI anotherURI =fileSystemManager.resolveFile("https://asd.com/somestuff/another.html").getURI();

        String result = baseURI.relativize(anotherURI).getPath();

        System.out.println(result);
    }
}

Maybe you need to add module to run the code:
https://mvnrepository.com/artifact/commons-httpclient/commons-httpclient

How to extract the relative url from the absolute url in Java

7 Answers7