Java - Servlet 404 error

Question

I am a newbie in servlet programming.

The following is my sample servlet code

Sample.Java

public class Sample extends HttpServlet {
    protected void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {
        res.setContentType("text/html");  
        PrintWriter pw=res.getWriter();  

        String name=req.getParameter("name");//will return value  
        pw.println("Welcome "+name);  
        pw.close();  
    }
}

Web.xml

<web-app>
<servlet>
<servlet-name>sampleservlet</servlet-name>
<servlet-class>Sample</servlet-class>
<load-on-startup>1</load-on-startup> 
</servlet>
<servlet-mapping>
<servlet-name>sampleservlet</servlet-name>
<url-pattern>/Sample</url-pattern>
</servlet-mapping>
</web-app>

Index.html

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>
<form action="Sample" method="get">  
Enter your name<input type="text" name="name"><br>  
<input type="submit" value="login">  
</form>  
</body>
</html>

My problem

When I right click on my project and then click Run as -> Run on server, I select the server, it asks me for to select a server and then I select the server to run. In the eclipse window a browser window is opened which has the address URL as http://localhost:8080/Sample/

enter image description here

When I click on login it gives me an error like this,

HTTP Status 404 - /Sample/welcome

type Status report

message /Sample/welcome

description The requested resource is not available.

Apache Tomcat/7.0.62

Screenshot

enter image description here

Why am I getting an error like this ?

Other details

Server:apache-tomcat-7.0.62 IDE: Eclipse Java EE kepler

Steps I tried to solve the problem

I tried these,

Getting HTTP Status 404 error when trying to run servlet

Result

I did not see the .class files in WEB-INF folder.

Tomcat giving 404 error with servlets

Result In this path "tomcat7\work\Catalina\localhost\your app",the work folder was empty.

Please let me know if I need to post any more details.

Directory structure from IDE

enter image description here

It would be helpful to see project structure/tree. Maybe by screenshot from IDE — Stan, Jun 16 '15 at 11:56
Thanks. So 'Sample' is your application name and servlet is mapped to '/Sample' URL inside your application. I think you should try to submit your form to the url 'Sample/Sample' (put it to Action attribute). First you can simply try in browser http://localhost:8080/Sample/Sample — Stan, Jun 16 '15 at 12:04
It is weird. You have written `form action = Sample` but it is looking for `Sample/welcome`. Try to first rename your Servlet or Project, don't keep their name same. And then lets see what happens. — gprathour, Jun 16 '15 at 12:09
by clicking on login the url would be like http://localhost:8080/Sample/Sample?name=StackOverflow because your form action is sample.. — Hiren, Jun 16 '15 at 12:10
@GPRathour I changed the servlet name from `sampleservlet` to `newserv` but I am getting the above same error.Please let me know what other details can I provide you ? — oldcode, Jun 16 '15 at 12:20
Add to the META-INF folder a context.xml file with this content: — Zelldon, Jun 16 '15 at 12:22
No no. I din't mean that. I meant either change your Project name from `Sample` to like `SampleProject` or change the name of servlet class from `Sample` to `MyServlet` etc. — gprathour, Jun 16 '15 at 12:22
@GPRathour I renamed the project from `sample` to `Sampleproject` . I am still getting the same error. Please see [this](http://postimg.org/image/rm7ch4td5/). — oldcode, Jun 16 '15 at 12:41
@Zelldon I have added the `context.xml` file. Please see [this](http://postimg.org/image/rm7ch4td5/) — oldcode, Jun 16 '15 at 12:42

PbxMan · Accepted Answer · 2015-06-16T14:00:57.187

2

Your code does work for me in tomcat 7 and eclipse. Perhaps your index.html is not the same as the one your are posting because it's aimnig at Sample/welcome instead of Sample/Sample.

Tips:

Make sure your index.html published version is the same as the one you have in your code. Modify the content and make sure it's publishing properly.
Load http://localhost:8080/Sample/Sample?name=Random directly in your browser to see that the servlet is working propertly.
Double click on Tomcat7 on your servers. Go to your Server path. e.g. C:\Java\workspace.metadata.plugins\org.eclipse.wst.server.core\tmp2\wtpwebapps\Sample\WEB-INF\classes (your Sample class should be there) double check if you have permissions in those folders.
Export your project as a WAR and deploy it directly in your tomcat without eclipse.
Clean/Build your project
On your Package Explorer under Servers/server.xml a you should have a declared context e.g. <Context docBase="Sample" path="/Sample" reloadable="false" source="org.eclipse.jst.jee.server:Sample"/></Host> If you don't double check permisions in those folders. Add your tomcat7 server from the start again.

enter image description here

edited Jun 16 '15 at 14:00

answered Jun 16 '15 at 12:45

PbxMan

7,525
1
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I have changed `
` to `
`, I am getting the above same error. Please let me know if I am doing something wrong.
– oldcode Jun 16 '15 at 12:52
I tried your second tip. I am still getting the same error. What could be wrong ? – oldcode Jun 16 '15 at 12:56
@Codester Use
Please, Enter your name
instead, let me know if you see the "Please, Enter..." I think the server is not refreshing your changes properly.
– PbxMan Jun 16 '15 at 12:57
`
Please, Enter your name

` Still I am getting the same error. – oldcode Jun 16 '15 at 13:15

score 1 · Answer 2 · edited Jun 29 '18 at 13:43

Try this and you don't need to write the XML file for any servlet ;)

Just add the annotation @WebServlet("/urlpattern") and call this URL-pattern inside the JSP from <form action="urlpattern">

Only if you work on Eclipse.

@WebServlet("/Sample")
public class Sample extends HttpServlet {
protected void doGet(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException {

    res.setContentType("text/html");  
    PrintWriter pw = res.getWriter();  

    String name = req.getParameter("name"); //will return value  
    pw.println("Welcome "+name);  
    pw.close();  
}}

Hope it helps.

Java - Servlet 404 error

2 Answers2

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