How to retain trailing zeroes when converting BigDecimal to String

Question

I have to convert a BigDecimal value, e.g. 2.1200, coming from the database to a string. When I use the toString() or toPlainString() of BigDecimal, it just prints the value 2.12 but not the trailing zeroes.

How do I convert the BigDecimal to string without losing the trailing zeroes?

Related: http://stackoverflow.com/questions/4051887/how-to-format-a-java-string-with-leading-zero — Thomas Weller, Jun 17 '15 at 14:02
possible duplicate of [How to nicely format floating numbers to String without unnecessary decimal 0?](http://stackoverflow.com/questions/703396/how-to-nicely-format-floating-numbers-to-string-without-unnecessary-decimal-0) — Thomas Weller, Jun 17 '15 at 14:04

score 6 · Answer 1 · edited Jul 25 '16 at 13:47

6

try this..

MathContext mc = new MathContext(6); // 6 precision
BigDecimal bigDecimal = new BigDecimal(2.12000, mc);
System.out.println(bigDecimal.toPlainString());//2.12000

edited Jul 25 '16 at 13:47

Ende Neu

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answered Jun 17 '15 at 14:01

Hiren

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This doesn't answer OP's question, when he's got a BigDecimal already in hand . . . – GingerHead Jun 17 '15 at 14:10
yes it was my mistake now look at my answer @GingerHead btw thanks!! – Hiren Jun 17 '15 at 14:16
This assumes that 6 is the required precision always. – Naveed S Feb 13 '18 at 15:28
It didnt work for me.. The below code printing "100.25" `MathContext mc = new MathContext(6); BigDecimal i = new BigDecimal(100.250, mc); System.out.println(i.toPlainString());` And also what if I have to convert the BigDecimal object which returned from an method to String ? Here you hardcoaded the value right? – sparker May 09 '18 at 10:00
Yes @PadmanabhanVijendran the precision is hardcoded. I did not get you about the conversion. Please elaborate it or post a new question with what you tried, what you achieved and where you are facing the issue. – Hiren May 10 '18 at 05:23

Davide Lorenzo MARINO · Answer 2 · 2015-06-17T14:28:09.947

2

To convert a BigDecimal to a String with a particular pattern you need to use a DecimalFormat.

BigDecimal value = .... ;
String pattern = "#0.0000"; // If you like 4 zeros
DecimalFormat myFormatter = new DecimalFormat(pattern);
String output = myFormatter.format(value);
System.out.println(value + " " + pattern + " " + output);

To check the possible values of pattern see here DecimalFormat

edited Jun 17 '15 at 14:28

answered Jun 17 '15 at 14:04

Davide Lorenzo MARINO

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Can you specify what a `value` is ? – GingerHead Jun 17 '15 at 14:25
value is your BigDecimal. I edited the answer to show it – Davide Lorenzo MARINO Jun 17 '15 at 14:27
I know exactly what it is . . . – GingerHead Jun 17 '15 at 14:28

Gaurav vijayvargiya · Answer 3 · 2017-06-23T09:12:52.510

0

double value = 1.25;
// To convet double to bigdecimal    
BigDecimal bigDecimalValue = BigDecimal.valueOf(value);   
//set 4 trailing value
BigDecimal tempValue = bigDecimalValue.setScale(4, RoundingMode.CEILING);
System.out.println(tempValue.toPlainString());

edited Jun 23 '17 at 09:12

answered Jun 23 '17 at 09:05

Gaurav vijayvargiya

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score 0 · Answer 4 · answered Jun 27 '17 at 04:20

0

You can use below code .

    BigDecimal d = new BigDecimal("1.200");
    System.out.println(d);
    System.out.println(String.valueOf(d));

Output is as below :
1.200 1.200

answered Jun 27 '17 at 04:20

Nishant Bhardwaz

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score -2 · Answer 5 · answered Nov 19 '20 at 13:25

-2

In a practical way, just don't use BigDecimal, instead use toString() of Double class.

answered Nov 19 '20 at 13:25

TheArrowster

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How to retain trailing zeroes when converting BigDecimal to String

5 Answers5