Comparing timespec values

Question

What's the best way to compare two timespec values to see which happened first?

Is there anything wrong with the following?

bool BThenA(timespec a, timespec b) {
    //Returns true if b happened first -- b will be "lower".
    if (a.tv_sec == b.tv_sec)
        return a.tv_nsec > b.tv_nsec;
    else
        return a.tv_sec > b.tv_sec;
}

This Looks good to me – Thomas Sparber Jun 17 '15 at 15:30 — Thomas Sparber, Jun 17 '15 at 15:30

score 8 · Answer 1 · answered Jun 17 '15 at 15:51

8

Another way you can go this is to have a global operator <() defined for timespec. Then you can just you that to compare if one time happened before another.

bool operator <(const timespec& lhs, const timespec& rhs)
{
    if (lhs.tv_sec == rhs.tv_sec)
        return lhs.tv_nsec < rhs.tv_nsec;
    else
        return lhs.tv_sec < rhs.tv_sec;
}

Then in you code you can have

timespec start, end;
//get start and end populated
if (start < end)
   cout << "start is smaller";

answered Jun 17 '15 at 15:51

NathanOliver

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For this to work he has to decide if this a C or C++ question. It's currently tagged as both. – Brian McFarland Jun 17 '15 at 16:13
1

@BrianMcFarland True. I came in from the C++ side so I didn't see the C tag. – NathanOliver Jun 17 '15 at 16:14
It could be either depending on circumstances. – Pat Flegit Jun 17 '15 at 16:22

Comparing timespec values

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