Let's say i have the letters a,b,s,d (say)
I have 100s of words in an array.
I want to use js to search for a word containing all the letters, and only if all letters are met, then return that word.
How do i do it?
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Ashwin Alaparthi
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You may have to learn regular expressions, or do lots of conditional statements with `.indexOf(char) != -1`. – area28 Jun 17 '15 at 15:51
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1There are plenty of other post on SO that can help you. – shammelburg Jun 17 '15 at 15:52
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1Possible duplicate of [How can search a string to see if it contains all substrings?](http://stackoverflow.com/questions/18147499/how-can-search-a-string-to-see-if-it-contains-all-substrings) – apsillers Jun 17 '15 at 15:53
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If you're reading this, @user4703663, please undelete your post. I was working off an incorrect copy. It works just fine and would be happy to upvote. – Andy Jun 17 '15 at 16:16
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God, I feel really bad now. – Andy Jun 17 '15 at 16:37
1 Answers
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OK, so here's an expanded version of the code originally posted by user4703663. I wanted to wait until they had a chance to undelete their answer but they never did.
var words = ['absd', 'dfsd', 'dsfefe', 'dfdddr', 'dfsgbbgah', 'dfggr'];
var str = 'absd';
function find(words, str) {
// split the string into an array
str = str.split('');
// `filter` returns an array of array elements according
// to the specification in the callback when a new word
// is passed to it
return words.filter(function(word) {
// that callback says to take every element
// in the `str` array and see if it appears anywhere
// in the word. If it does, it's a match, and
// `filter` adds that word to the output array
return str.every(function(char) {
return word.includes(char);
});
});
}
const output = find(words, str); // [ "absd", "dfsgbbgah" ]
console.log(output);

Andy
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