How to create dict from date (in strings) range?

Question

I have two dates as strings:

start = '2015-01-01'
end = '2015-03-23'

And I want to create dict like this (I use OrderedDict):

date_dict = {
    '2015-01-01': [something],
    '2015-01-02': [something],
    '2015-01-03': [something],
    '2015-01-04': [something],
    [...]
    '2015-03-22': [something],
    '2015-03-23': [something],
}

How to generate keys from this two strings?

http://stackoverflow.com/a/7274316/4907653 – f43d65 Jun 18 '15 at 10:10 — f43d65, Jun 18 '15 at 10:10
Are your date always saved as strings? – Iron Fist Jun 18 '15 at 10:13 — Iron Fist, Jun 18 '15 at 10:13

score 1 · Accepted Answer · answered Jun 18 '15 at 10:16

Try something like the below code to generate the keys -

from datetime import datetime as dt, timedelta as td
start = '2015-01-01'
end = '2015-03-23'
sd = dt.strptime(start,'%Y-%m-%d')
ed = dt.strptime(end,'%Y-%m-%d')
delta = ed - sd
for i in range(delta.days+1):
    dict[sd + td(days=i)] = <something>

How to create dict from date (in strings) range?

1 Answers1