If you want to do it with one regexp, replace
accepts a function as the replacer so you could leverage that with a group match:
var str = 'some string <br/> and something else';
var txt = str.replace(/(<br\s*\/?>| )/mg, function (match) {
return match === ' ' ? ' ' : '\n';
});
document.write('<pre>' + txt + '</pre>');
If not, you can also chain together as many replace
calls as you want:
var str = 'some string <br/> and something else';
var txt = str.replace(/<br\s*\/?>/gm, '\n').replace(/ /gm, ' ');
document.write('<pre>' + txt + '</pre>');
The main benefit of using one replace
is that it won't need to check the entire string twice. However this does make the code a bit harder to read and possibly to maintain if you need to add/edit which entities you want to replace. So depending on the length of the string to be checked you would need to strike a balance between performance and readability/maintainability.