Swing regular expression for phone number validation

Question

I want to validate phone number field in swing, so I am writing code to allow user to enter only digits, comma, spaces. For this I am using regular expression, when user enter characters or other than the pattern text field will consume.

My code is not working. Can anyone tell me what the problem is?

String s = c_phone.getText();
    Pattern pattern = Pattern.compile("([0-9\\-\\(\\)\\,]+)");
    Matcher m = pattern.matcher(s);
    if((!m.matches())){
        evt.consume();
    }

Thanks in advance.

Please refer to http://stackoverflow.com/questions/123559/a-comprehensive-regex-for-phone-number-validation — kmanu, Jun 22 '15 at 12:32

Wiktor Stribiżew · Accepted Answer · 2015-06-22T13:27:50.377

1

To only allow digits, comma and spaces, you need to remove (, ) and -. Here is a way to do it with Matcher.find():

Pattern pattern = Pattern.compile("^[0-9, ]+$");
...
if (!m.find()) {
  evt.consume(); 
}

And to allow an empty string, replace + with *:

Pattern pattern = Pattern.compile("^[0-9, ]*$");

edited Jun 22 '15 at 13:27

answered Jun 22 '15 at 12:32

Wiktor Stribiżew

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private void c_phoneKeyReleased(java.awt.event.KeyEvent evt) { // TODO add your handling code here: String s = c_phone.getText(); Pattern pattern = Pattern.compile("^[0-9, ]*$"); //Pattern pattern = Pattern.compile("([0-9\\-\$\$\\,]+)"); Matcher m = pattern.matcher(s); if((!m.matches())){ evt.consume(); } } – Thirunavukkarasu Jun 22 '15 at 12:42

score 0 · Answer 2 · answered Jun 22 '15 at 12:29

0

Your character class includes digits, hyphens, commas and parenthesis.

Note that you do not need to escape the commas and parenthesis, nor the hyphen if placed correctly in the character class.

To validate...

only digits, comma, spaces

"[0-9, ]+" should suffice.

answered Jun 22 '15 at 12:29

Mena

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its fine, but here also, the textfield is accepting to enter all the characters and numbers. – Thirunavukkarasu Jun 22 '15 at 12:33
@Thirunavukkarasu not if you use `matches`. – Mena Jun 22 '15 at 12:48

TheCodingFrog · Answer 3 · 2015-06-22T15:10:41.797

0

You can use something like below,

String s = "203 555 0000";
        String s1 = "203,550,0000";
        String s2 = "2035500000";
        Pattern pattern = Pattern.compile("\\d{3}[,\\s]?\\d{3}[,|\\s]?\\d{4}$");
        Matcher m = pattern.matcher(s);
        if(m.matches()){
            //evt.consume();
            System.out.println("Matches");
        }

Explained below:

\d matches a digit.
{3} is a quantifier that, following \d, matches exactly three digits.
| (the vertical bar) indicates alternation, that is, a given choice of alternatives.
\s - matches space
$ matches the end of a line.

You can enhance it further depend upon your use case.

edited Jun 22 '15 at 15:10

answered Jun 22 '15 at 12:48

TheCodingFrog

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FYI: `[,|\\s]?` matches 0 or 1 `,` or `|` or a whitespace. `|` is not an alternation operator inside a character class. – Wiktor Stribiżew Jun 22 '15 at 13:23
Thanks for the correction, I have corrected it now. – TheCodingFrog Jun 22 '15 at 15:11

Swing regular expression for phone number validation

3 Answers3