How to get a pizza program to round to a full pizza In PYTHON

Question

so i'm making a pizza program in Python 3.3 that takes input from the user and prints the amount of pizza's needed. Every pizza is cut into 8 slices. So it works like this: You input the amount of people coming to the party, and how many pieces EVERYONE will eat on average. The computer then tells you how many pizza's you need to order. My problem is, say 10 people are coming to the party, and they will eat 2 pieces each on average. The computer gives me 2.5, and I need to find a way for it to round to the nearest full number up. See what I mean? Here is my code so far

 eaters = input("How many people are attending the party?")

 pieces = input("How many pieces will everyone eat on average?")

 pizzas = float(eaters) * float(pieces)
 orders_needed = pizzas/8
 print(orders_needed)

Any ideas on how I can do this?

If `eaters` and `pieces` are integers, you can simply do `orders_needed = (eaters * pieces + 7)/8` — vacawama, Jun 22 '15 at 17:22
in python 3, those ints get converted to floats when you do /8; you need to do //8 (He pointed out it is python 3.3) — Berserker, Oct 01 '17 at 16:13

score 2 · Accepted Answer · answered Jun 22 '15 at 17:09

2

math.ceil rounds up.

import math

eaters = input("How many people are attending the party?")

pieces = input("How many pieces will everyone eat on average?")

pizzas = float(eaters) * float(pieces)
orders_needed = math.ceil(pizzas/8)
print(orders_needed)

answered Jun 22 '15 at 17:09

ashwinjv

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note that `math.ceil` returns a `float`, so you probably want to wrap it in an `int()` – Ryan Haining Jun 22 '15 at 17:10
@RyanHaining: In Python 3, `math.ceil` returns an `int`. – Mark Dickinson Jun 22 '15 at 18:49

How to get a pizza program to round to a full pizza In PYTHON

1 Answers1