Printing out errors with Requests library

Question

I've been reading through http://www.mobify.com/blog/http-requests-are-hard/ , which discusses various types of errors which can be encountered with a request. The article focuses on catching each one. I would like to simply print out the error type whenever any error occurs. In the article , one example is:

url = "http://www.definitivelydoesnotexist.com/"

try:
    response = request.get(url)
except requests.exceptions.ConnectionError as e:
    print "These aren't the domains we're looking for."

Is there a way to rewrite the last 2 lines in pseudocode as:

except requests.ANYERROR as e:
    print e

`except Exception as e:print(e.message)`? – Padraic Cunningham Jun 22 '15 at 22:19 — Padraic Cunningham, Jun 22 '15 at 22:19

score 4 · Accepted Answer · edited May 23 '17 at 12:22

4

From my other answer:

All exceptions that Requests explicitly raises inherit from requests.exceptions.RequestException.

So this should catch everything:

try:
    response = requests.get(url)
except requests.exceptions.RequestException as e:
    print e

edited May 23 '17 at 12:22

Community

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answered Jun 22 '15 at 22:21

Jonathon Reinhart

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This won't catch a ValueError though, `data = response.json()` – Padraic Cunningham Jun 22 '15 at 22:23
@PadraicCunningham Um, yeah, because that line of code is no where in the original post. – Jonathon Reinhart Jun 22 '15 at 22:24
You should have a read of the blog – Padraic Cunningham Jun 22 '15 at 22:27
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One should expect a completely different class of errors when making an HTTP request and when interpreting the text contained in the response. They're totally separate things. Catching `Exception` is never a good idea IMO, except at a top-level exception handler who's going to log and exit, or make a crash dump, etc. – Jonathon Reinhart Jun 22 '15 at 22:31
Besides, a two-second look at [the docs](http://docs.python-requests.org/en/latest/user/quickstart/#json-response-content) indicates that `.json()` can raise a `ValueError`. – Jonathon Reinhart Jun 22 '15 at 22:32
where did I say it could not raise a ValueError? If it is only about requests then you should mark it as a dupe. – Padraic Cunningham Jun 22 '15 at 22:33
I will delete my answer and dupe it – Padraic Cunningham Jun 22 '15 at 22:36

score 1 · Answer 2 · answered Jun 22 '15 at 22:25

1

All of the requests exceptions inherit from requests.exceptions.RequestException, so you can:

try:
    ....
    ....
except requests.exceptions.RequestException as e:
    # Do whatever you want to e
    pass

answered Jun 22 '15 at 22:25

Dekel

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This is *exactly* what I posted 4 minutes prior. Duplicating answers just clutters up the site. – Jonathon Reinhart Jun 22 '15 at 22:28
You are correct. By the time I did the post you already posted yours. – Dekel Jun 22 '15 at 22:34

Printing out errors with Requests library

2 Answers2