How to convert a seconds series since 2012-01-01 0:0:0 to a time format expression.
And the inverse?
Convert a time expression, such as 2015-6-23 10:00:00, to the seconds since 2012-01-01 0:0:0.
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Roger Oliveira
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Orion_gi
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[`timedelta`](https://docs.python.org/3.5/library/datetime.html#timedelta-objects) – behzad.nouri Jun 23 '15 at 01:55
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possible duplicate of [Converting string into datetime](http://stackoverflow.com/questions/466345/converting-string-into-datetime) – tripleee Jun 23 '15 at 03:34
1 Answers
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import datetime as dt
print (dt.datetime(2015,1,2) - dt.datetime(2015,1,1)).total_seconds()
print dt.datetime(2015,1,1) + dt.timedelta(seconds=3600*24)
the output
http://testedanswers.com/questions/-JsT943k5Y8lTp2dOb3s
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JuanPablo
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`(dt.datetime(2015,1,1) + dt.timedelta(seconds=3600*24)).strftime("%Y-%m-%d %H:%m:%S")` – JuanPablo Jun 24 '15 at 12:32