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I have two sets of dates

Testday<-as.Date(c("2015-06-25", "2015-06-25","2015-06-25"))
DOB<-as.Date(c("2012-03-15", "2004-04-21","2014-07-25"))

I want to calculate the age, correct to 2 decimal places.

On Excel, I would simply do this: (Testday - DOB)/365.25

and obtain these ages: 3.28, 11.18, 0.92

Is there anyway I could perform this on R too?

Head and toes
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1 Answers1

0

Is this OK?

round(as.numeric((Testday - DOB) / 365.25), 2)
#[1]  3.28 11.18  0.92
Tom Liptrot
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