how to run a C code with argc argv from python?

Question

I need to run my c code from python, usually as adviced here I do this and works perfectly:

from subprocess import call
call(["./code", "args", "to", "code"])

I would like to run the code that in order to run needs argv, as a number, so for instance normally from shell I should call simply:

./code #certainNumber

I would like to pass a string at the call function, like:

D=1
str = "./code %d"(%D)
call([str, "args", "to", "code"])

obviously this does not work. I would like to chose from python the parameter that I need to insert in my c code.

thanks

You can pass a number, but you can't pass argv itself. argv is handled automatically. — Kenny Ostrom, Jun 25 '15 at 14:26
`call(["./code", str(variableContainingNumber), "other", "args"])`, perhaps? — twalberg, Jun 25 '15 at 14:47
A side note: if you feel like experimenting, cython is getting very good at doing things like these. — Karpov, Jun 25 '15 at 15:16
@twalberg, can we call directly call(["C:\Users\Documents\sample.c"]) ? — Anjali, Dec 06 '17 at 09:45
@Anjali No. C code needs to be compiled into a runable binary program first - otherwise it's just a text file. — twalberg, Dec 06 '17 at 12:48

score 0 · Accepted Answer · answered Jun 26 '15 at 12:27

0

As twalberg said this works perfectly:

call(["./code", str(variableContainingNumber), "other", "args"])

answered Jun 26 '15 at 12:27

user3585292

score -1 · Answer 2 · answered Jun 26 '15 at 01:09

-1

You could always do the following

import os

# arguments is some list of arguments as strings
output = os.system(processname + " ".join(arguments))

answered Jun 26 '15 at 01:09

AndrewGrant

2 Answers2