Python: How to graph $y^2=x^3-7+3$?

Question

I have been searching online but I can't find a way to do it.

You're saying you googled 'how to graph in python' and found nothing? [First link](http://matplotlib.org/users/pyplot_tutorial.html) — Leb, Jun 26 '15 at 01:29
`x^3-7+3` is the same as `x^3-4`. Did you mean `x^3-7x+3` perhaps? — unutbu, Jun 26 '15 at 01:35

unutbu · Answer 1 · 2015-06-26T01:58:53.780

3

Matplotlib's contour function can be used to plot the solution to implicit equations:

import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()

y, x = np.ogrid[-4:4:1000j, -6:6:1000j]
plt.contour(
    x.ravel(), y.ravel(), y**2 - x**3 + 7*x -3, [0])
plt.show()

yields

enter image description here

edited Jun 26 '15 at 01:58

answered Jun 26 '15 at 01:33

unutbu

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score 0 · Answer 2 · answered Jun 26 '15 at 01:28

With matplotlib and numpy:

import matplolib.pyplot as plt
import numpy as np
from math import sqrt

x = np.arange(10,100) # You have to choose the domain you are looking to plot
y = [sqrt(i**3 - 7 + 3) for i in x]

plt.plot(x,y)
plt.show()

Well, actually you have to be careful with the domain of the function, in order to choose +sqrt or -sqrt.

Python: How to graph $y^2=x^3-7+3$?

2 Answers2