Given input:
[{ a: 1 }, { b: 2 }, { c: 3 }]
How to return:
{ a: 1, b: 2, c: 3 }
For arrays it's not a problem with lodash but here we have array of objects.
Given input:
[{ a: 1 }, { b: 2 }, { c: 3 }]
How to return:
{ a: 1, b: 2, c: 3 }
For arrays it's not a problem with lodash but here we have array of objects.
Use Object.assign
:
let merged = Object.assign({}, ...arr); // ES6 (2015) syntax
var merged = Object.assign.apply(Object, arr); // ES5 syntax
Note that Object.assign
is not yet implemented in many environment and you might need to polyfill it (either with core-js, another polyfill or using the polyfill on MDN).
You mentioned lodash, so it's worth pointing out it comes with a _.assign
function for this purpose that does the same thing:
var merged = _.assign.apply(_, [{ a: 1 }, { b: 2 }, { c: 3 }]);
But I really recommend the new standard library way.
With lodash, you can use merge():
var arr = [ { a: 1 }, { b: 2 }, { c: 3 } ];
_.merge.apply(null, [{}].concat(arr));
// → { a: 1, b: 2, c: 3 }
If you're doing this in several places, you can make merge()
a little more elegant by using partial() and spread():
var merge = _.spread(_.partial(_.merge, {}));
merge(arr);
// → { a: 1, b: 2, c: 3 }
Here is a version not using ES6 methods...
var arr = [{ a: 1 }, { b: 2 }, { c: 3 }];
var obj = {};
for(var i = 0; i < arr.length; i++) {
var o = arr[i];
for(var key in o) {
if(typeof o[key] != 'function'){
obj[key] = o[key];
}
}
}
console.log(obj);
fiddle: http://jsfiddle.net/yaw3wbb8/
You can use underscore.extend function like that:
var _ = require('underscore');
var a = [{ a: 1 }, { b: 2 }, { c: 3 }];
var result = _.extend.apply(null, a);
console.log(result); // { a: 1, b: 2, c: 3 }
console.log(a); // [ { a: 1, b: 2, c: 3 }, { b: 2 }, { c: 3 } ]
And to prevent modifying original array you should use
var _ = require('underscore');
var a = [{ a: 1 }, { b: 2 }, { c: 3 }];
var result = _.extend.apply(null, [{}].concat(a));
console.log(result); // { a: 1, b: 2, c: 3 }
console.log(a); // [ { a: 1 }, { b: 2 }, { c: 3 } ]
Adding to the accepted answer, a running code snippet with ES6.
let input = [{ a: 1 }, { b: 2 }, { c: 3 }]
//Get input object list with spread operator
console.log(...input)
//Get all elements in one object
console.log(Object.assign(...input))
I've got a neat little solution not requiring a polyfill.
var arr = [{ a: 1 }, { b: 2 }, { c: 3 }];
var object = {};
arr.map(function(obj){
var prop = Object.getOwnPropertyNames(obj);
object[prop] = obj[prop];
});
Hope that helps :)
Here is a nice usage of Object.assign
with the array.prototype.reduce
function:
let merged = arrOfObjs.reduce((accum, val) => {
Object.assign(accum, val);
return accum;
}, {})
This approach does not mutate the input array of objects, which could help you avoid difficult to troubleshoot problems.
You can easily flat your object to array.
function flatten(elements) {
return elements.reduce((result, current) => {
return result.concat(Array.isArray(current) ? flatten(current) : current);
}, []);
};
6 years after this question was asked.
Object.assign is the answer (above) I like the most.
but is this also legal ?
let res = {};
[{ a: 1 }, { b: 2 }, { c: 3 }].forEach(val => {
let key = Object.keys(val);
console.log(key[0]);
res[key] = val[key];
})
With more modern spread operator
arrOfObj.reduce( (acc, curr) => ({ ...acc, ...cur }) );
const data = [
[{ a: "a" }, { b: "b" }, { c: "c" }],
[{ d: "d" }, { e: "e" }, { f: "f" }],
[{ g: "g" }, { h: "h" }, { i: "i" }],
];
function convertToObject(array){
const response = {};
for (let i = 0; i < array.length; i++) {
const innerArray = array[i];
for (let i = 0; i < innerArray.length; i++) {
const object = innerArray[i];
const keys = Object.keys(object);
for (let j = 0; j < keys.length; j++) {
const key = keys[j];
response[key] = object[key];
}
}
}
return response;
}
console.log(convertToObject(data));
function carParts(manufacturer, model, ...parts) {
return { manufacturer, model, ...Object.assign(...parts) };
}
console.log(
carParts(
"Honda",
"2008",
{ color: "Halogen Lights" },
{ Gears: "Automatic Gears" },
{ LED: "Android LED" },
{ LED: "Android LED1" }
)
);
This is how i have done.