Zip every element of list A with every element of list B - best "pythonie" way of doing this

Question

I have two lists which I want to zip

List A:

["hello ", "world "]

List B:

["one", "two", "three"]

I want to zip the elements in the lists like so:

[("hello","one")
("hello","two")
("hello","three")
("world","one")
("world","two")
("world","three")]

Obviously, I can use a double for loop and append the elements but I am wondering what would be a good pythonie way of doing this?

The concept you are describing is the "[Cartesian product](https://en.wikipedia.org/wiki/Cartesian_product)" and can be achieved using `itertools.product` as shown in the above link. — Cory Kramer, Jun 30 '15 at 17:46

score 5 · Answer 1 · answered Jun 30 '15 at 17:45

5

This seems like a perfect use-case for itertools.product

>>> import itertools
>>> list(itertools.product(['hello', 'world'], ['one', 'two', 'three']))
[('hello', 'one'), ('hello', 'two'), ('hello', 'three'), ('world', 'one'), ('world', 'two'), ('world', 'three')]

answered Jun 30 '15 at 17:45

mgilson

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Yep. That's what I was looking for. Cartesian product, as @CoryKramer mentioned. – Georgi Angelov Jun 30 '15 at 17:48

Zip every element of list A with every element of list B - best "pythonie" way of doing this

1 Answers1