if name == main PHP to protect my code

Question

I am somehow a noobie in PHP and I want to learn. I am making a proyect, in which I use require('parts/header.php') statements to include functions and templates. My pages look like this:

<?php 
include('core/checklogin.php');
//This will check if the user is logged in and can see this page or not
include('parts/top.php');
//This loads the <head> tags and the header, including the navbar
?>

<section id="mainArea">
    <h1>Hello <?php echo getUserNickname()?></h1>
    <p>Some stuff</p>
</section>

<?php 
include('parts/bottom.php');
//This loads the <head> tags and the header, including the navbar
?>

The problem is if someone enters myproyect.com/parts/top.php he would see the top part, and that file is going to be executed. I don't want that. I was thinking doing some stuff in a .htaccess file like:

 #.htaccess inside parts directory
 dont_serve_anything_inside_this_directory_and_return_forbidden();

But I don't know how without affecting the server side code. Another alternative is to use the equivalent of if __name__ == 'main': of python, and do like:

 //parts/top.php
 if(__name__ == 'main'){
     header('Location: /index.php');
     exit();
 }

What could I do?

move top.php outside the web root, then there is no access via the web-server — , Jun 30 '15 at 22:33

score 0 · Accepted Answer · answered Jun 30 '15 at 22:34

You need to create file .htaccess inside your so-called protected from the outside direct access folder and put the following content there:

Deny from all

This will prevent users from being able to access your files using http://example.com/parts/bottom.php

Just add .htacccess to parts folder.

if __name__ == main PHP to protect my code

1 Answers1

if name == main PHP to protect my code