It is an interesting question.
It is possible to statically-initialize a std::map as follows:
static const std::map<int, int> my_map {{1, 2}, {3, 4}, {5, 6}};
but I get that such initialization is not what you are looking for, so I took another approach after looking at your example.
A global registry holds a mapping between function name (an std::string
) and run time (an std::size_t
representing the number of milliseconds).
An AutoProfiler
is constructed providing the name of the function, and it will record the current time. Upon destruction (which will happen as we exit the function) it will calculate the elapsed time and record it in the global registry.
When the program ends we print the contents of the map (to do so we utilize the std::atexit
function).
The code looks as follows:
#include <cstdlib>
#include <iostream>
#include <map>
#include <chrono>
#include <cmath>
using ProfileMapping = std::map<std::string, std::size_t>;
ProfileMapping& Map() {
static ProfileMapping map;
return map;
}
void show_profiles() {
for(const auto & pair : Map()) {
std::cout << pair.first << " : " << pair.second << std::endl;
}
}
class AutoProfiler {
public:
AutoProfiler(std::string name)
: m_name(std::move(name)),
m_beg(std::chrono::high_resolution_clock::now()) { }
~AutoProfiler() {
auto end = std::chrono::high_resolution_clock::now();
auto dur = std::chrono::duration_cast<std::chrono::milliseconds>(end - m_beg);
Map().emplace(m_name, dur.count());
}
private:
std::string m_name;
std::chrono::time_point<std::chrono::high_resolution_clock> m_beg;
};
void foo() {
AutoProfiler ap("foo");
long double x {1};
for(std::size_t k = 0; k < 1000000; ++k) {
x += std::sqrt(k);
}
}
void bar() {
AutoProfiler ap("bar");
long double x {1};
for(std::size_t k = 0; k < 10000; ++k) {
x += std::sqrt(k);
}
}
void baz() {
AutoProfiler ap("baz");
long double x {1};
for(std::size_t k = 0; k < 100000000; ++k) {
x += std::sqrt(k);
}
}
int main() {
std::atexit(show_profiles);
foo();
bar();
baz();
}
I compiled it as:
$ g++ AutoProfile.cpp -std=c++14 -Wall -Wextra
and obtained:
$ ./a.out
bar : 0
baz : 738
foo : 7
You do not need -std=c++14
, but you will need at least -std=c++11
.
I realize this is not what you are looking for, but I liked your question and decided to pitch in my $0.02.
And notice that if you use the following definition:
using ProfileMapping = std::multi_map<std::string, std::size_t>;
you can record every access to each function (instead of ditching the new results once the first entry has been written, or overwriting the old results).