Redirect using webapp2 to capture the URL parameters

Question

I have written a code for a sign-up page asking for information like username, password and email. After the user gives correct input, the page is redirected to

'/welcome?username=name'

I am using the self.redirect. By using the methd redirect, I am getting the the new URL as '/welcome'. How will I include the query parameter? I also want the user_name to be displayed to the redirected page like :

Welcome name

How will I do this? This is the class I have written to handle '/welcome'

class welcomeHandler(webapp2.RequestHandler):
    def get(self):
        self.response.out.write("Welcome")

app = webapp2.WSGIApplication([
    ('/', MainHandler),('/welcome',welcomeHandler)], debug=True)

https://webapp-improved.appspot.com/api/webapp2.html#webapp2.redirect — NightShadeQueen, Jul 01 '15 at 16:52

score 2 · Answer 1 · answered Aug 10 '17 at 10:17

If you need to encode it, you can use this:

import urllib
self.redirect('/welcome?' + urllib.urlencode({'username': name})

If you ever need to add more query parameters, just add them to the dictionary, as shown in How to urlencode a querystring in Python?.

score 1 · Accepted Answer · answered Sep 03 '15 at 14:18

1

You need to use string substitution. Suppose you are storing the username in name. Thus you need to write :

self.redirect("/Welcome/username="+name)

answered Sep 03 '15 at 14:18

Richa Tibrewal

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score 0 · Answer 3 · answered Jul 16 '15 at 07:13

Why would you want to handle the user greeting like that? Either pass it as a template variable or do it as following:

class welcomeHandler(webapp2.RequestHandler):
    def get(self):
        self.response.out.write("Welcome %s") % username

Also, make sure you create a session for the user once they've signed up, otherwise you're just creating their credential but not actually logging them in.

Redirect using webapp2 to capture the URL parameters

3 Answers3