Loop back to beginning of code if input doesn't match REGEX | Python 2.7

Question

I'm trying to make my code loop back to the beginning until the user inputs something that matches the REGEX pattern.

For example:

userInput = raw_input('Enter text :')

if re.match("REGEX", userInput):
    #Do something

If the REGEX pattern does not match userInput, the code should ask them to enter userInput again until it matches the REGEX and there forth will do something. I am assuming a for loop is needed but I am not sure how to use it with REGEX.

<<< UPDATE >>>

Solution thanks to VKS:

while True:
    userInput = raw_input('Enter text :')
    if re.match("REGEX", userInput):
         break

score 1 · Accepted Answer · answered Jul 02 '15 at 18:00

1

while True:
    userInput = raw_input('Enter text :')
    if re.match("REGEX", userInput):
         break

You can do this simply

answered Jul 02 '15 at 18:00

vks

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Cheers, This really helped ;) – Enigmatic Jul 02 '15 at 18:12
@iAmNewToPYTHON glad it worked :) – vks Jul 02 '15 at 18:36

score 0 · Answer 2 · answered Jul 02 '15 at 17:59

0

Add a flag, set it to true, set it to false when a match occurs

do_loop = True

while do_loop:

    userInput = raw_input('Enter text :')

    if re.match("REGEX", userInput):
       #Do something
       do_loop = False

answered Jul 02 '15 at 17:59

Radu Diță

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Loop back to beginning of code if input doesn't match REGEX | Python 2.7

2 Answers2