Simple syntax for treating a instance method as a function

Question

In Java, we can do something like this:

ObservableStringValue str = ...;
Binding<Integer> strLen = EasyBind.map(str, String::length);

Where String::length effectively is an instance method being used as a function. Is there an equivalent form in Scala? (And by extension, an equivalent way to use EasyBind in Scala)

Also relevant: [Detach a method](http://stackoverflow.com/a/13473363/2988), [Difference between method and function in Scala](http://stackoverflow.com/q/2529184/2988), and [Scala: Referencing functions on object instances](http://stackoverflow.com/q/18899595/2988), among many many others. — Jörg W Mittag, Jul 06 '15 at 08:29

score 0 · Answer 1 · answered Jul 06 '15 at 08:37

0

scala> "dsfs".toString _
res1: () => String = <function0>

answered Jul 06 '15 at 08:37

Waldemar Wosiński

1,490
17
28

Simple syntax for treating a instance method as a function

1 Answers1