Deserialize JSON string in to Class

Question

I'm using JSON.NET in .NET 4.0. i receive a json string and try to put it in the class. but an exception happens and i cant solve it. here is my json string:

{
  "Records": [
    {
      "TransID": "902473653",
      "Date": "6/12/2015 10:47:00 AM",
      "ProductID": "90",
      "ItemDes": "test",
      "Amount": "20000",
      "BankTransactionID": "FM60aW33EavtDcYmXbz5vy/UvUAiQF",
      "Banktype": "IPG_SAMAN"
    },
    {
      "TransID": "910920749",
      "Date": "6/11/2015 11:05:00 AM",
      "ProductID": "91",
      "ItemDes": "test",
      "Amount": "20000",
      "BankTransactionID": "mAdWPNY++QdcKYepuIvuC4+UdZnQAa",
      "Banktype": "IPG_SAMAN"
    },
    {
      "TransID": "81131964",
      "Date": "11/24/2014 9:08:00 AM",
      "ProductID": "81",
      "ItemDes": "test",
      "Amount": "90000",
      "BankTransactionID": "123456789012",
      "Banktype": "USSD_InfoTech"
    }
  ]
}

my classes:

class Record
{
    public string TransID;
    public DateTime Date;
    public string ProductID;
    public string ItemDes;
    public string Amount;
    public string BankTransactionID;
    public string Banktype;
}
class Records
{
    public List<Record> data {get;set;}
}

my Deserializer code:

Records record;
record = new JavaScriptSerializer().Deserialize<Records>(result);
foreach (var item in record.data)
{
    textBox1.Text = item.TransID;
    textBox2.Text = item.Date.ToString();
    textBox3.Text = item.ProductID;
    textBox4.Text = item.Amount;
}

but it looks like record is null because null exceptions happen in foreach loop.

Your Json contains an *array* named `Records`, it doesn't have any `data` element. Your classes do not match your input — Panagiotis Kanavos, Jul 06 '15 at 08:34

Yuval Itzchakov · Accepted Answer · 2015-07-06T09:36:36.100

3

Your List<Record> property needs to be properly named. It should be "Records":

public class RootObject
{
    public List<Record> Records { get; set; }
}

This means you'll need to change the class name. In my example, it's called RootObject.

Or, you could annotate with the JsonProperty attribute:

public class Records
{
    [JsonProperty("Records")]
    public List<Record> Data { get; set; }
}

edited Jul 06 '15 at 09:36

answered Jul 06 '15 at 08:36

Yuval Itzchakov

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score 0 · Answer 2 · edited May 23 '17 at 12:29

0

You can use JsonProperty to change the name of the field. Please see this answer for more details: https://stackoverflow.com/a/15916121/686001

edited May 23 '17 at 12:29

Community

1
1

answered Jul 06 '15 at 08:48

Tibi

1,507
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10

Deserialize JSON string in to Class

2 Answers2