XML Parsing from Java Rest Service Response

Question

I am getting the below XML response from Java Rest Service.Could any one how to get status tag information?

<operation name="EDIT_REQUEST">
<result>
<status>Failed</status>
<message>Error when editing request details - Request Closing Rule Violation. Request cannot be Resolved</message>
</result>
</operation>

It is normal xml parsing problem, Have you tried anything yet ? — Naveen Ramawat, Jul 06 '15 at 13:19
See this : http://stackoverflow.com/questions/19396834/dom-xml-parser-example — Garry, Jul 06 '15 at 13:55
You could start by searching "how to parse xml in Java", your question is really lacking some research effort — gerrytan, Jul 06 '15 at 14:10

score 1 · Answer 1 · answered Jul 06 '15 at 13:38

A rough code is here

    ByteArrayInputStream input =  new ByteArrayInputStream(
            response.getBytes("UTF-8"));

    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    Document doc = builder.parse(input);

    // first get root tag and than result tag and childs of result tag
    NodeList childNodes = doc.getDocumentElement().getChildNodes().item(0).getChildNodes();
    for(int i = 0 ; i < childNodes.getLength(); i++){
        if("status".equals(childNodes.item(i).getNodeName())){
            System.out.println(childNodes.item(i).getTextContent());
        }
    }

score 1 · Answer 2 · answered Jul 06 '15 at 13:58

If you are just concerned with the status text, how about just having a simple regex with a group?

e.g.

String responseXml = 'xml response from service....'

Pattern p = Pattern.compile("<status>(.+?)</status>");
Matcher m = p.matcher(responseXml);

if(m.find())
{
   System.out.println(m.group(1)); //Should print 'Failed'
}

ring bearer · Accepted Answer · 2015-07-06T14:50:06.923

XPath is a very robust and intuitive way to quickly query XML documents. You can reach value of status tag by following steps.

   DocumentBuilderFactory documentBuilderFactory = DocumentBuilderFactory.newInstance();
   documentBuilderFactory.setNamespaceAware(true);
   DocumentBuilder builder = documentBuilderFactory.newDocumentBuilder();
   Document doc = builder.parse(stream); //input stream of response.

   XPathFactory xPathFactory = XPathFactory.newInstance();
   XPath xpath = xPathFactory.newXPath();

   XPathExpression expr = xpath.compile("//status"); // Look for status tag value.
   String status =  expr.evaluate(doc);
   System.out.println(status);

score -1 · Answer 4 · answered Jul 06 '15 at 13:43

-1

One option is to use the joox library, imported using gradle, like:

compile 'org.jooq:joox:1.3.0'

And use it like:

import org.xml.sax.SAXException;
import java.io.File;
import java.io.IOException;
import static org.joox.JOOX.$;

public class Main {

    public static void main(String[] args) throws IOException, SAXException {
        System.out.println(
                $(new File(args[0])).xpath("/operation/result/status").text()
        );
    }
}

It yields:

Failed

answered Jul 06 '15 at 13:43

Birei

35,723
2
77
82

1

This is not a gradle question, and there is no reason to add the burden of a third-party library to do something that can easily be done in with regular Java SE. – VGR Jul 06 '15 at 13:49

XML Parsing from Java Rest Service Response

4 Answers4