String created as literal and new operator

Question

When I declare a String using:

String a = new String("Hello");

2 objects are created. 1 object resides in heap and another in String literal pool.

So when I do:

String b = "Hello";

Is a new object created or is "Hello" from String pool referenced to b?

Does this not depend on the language used? – Jongware Jul 06 '15 at 14:27 — Jongware, Jul 06 '15 at 14:27
@SDC, is it Java? If yes, please tag it so. – Adam Stelmaszczyk Jul 06 '15 at 14:30 — Adam Stelmaszczyk, Jul 06 '15 at 14:30

score 0 · Answer 1 · edited May 23 '17 at 12:21

A new object is created.

Explanation

new String("Hello") creates one object on the heap. It is not stored in the String literal pool. More information here.
String b = "Hello" first wants to reuse String "Hello" from the pool, but there is none. So, it will create a new "Hello" String object in the pool and assign your reference to it.

You can read more about String literals in Java Language Specification 3.10.5.

We can test that the references are pointing to different objects:

String a = new String("Hello");
String b = "Hello";
System.out.println(a == b);

Prints false, as expected.

score 0 · Answer 2 · edited Jul 08 '15 at 00:48

0

I am talking about Java language. I have read in many places that

String a = new String("Hello")

creates 2 objects. One is in Heap. Could you please let me know where is the other object created?

edited Jul 08 '15 at 00:48

answered Jul 07 '15 at 13:19

SDC