What is a regular expression that find a line like this:

Question

I want a regular expression that could be used to find the following lines:

<rect width='10px' height ='20px'/>
<rect width='20px' height ='22px'/>
<circle radius='20px' height ='22px'/>

and replace them by the these lines:

<rect width='10px' height ='20px'></rect>
<rect width='20px' height ='22px'></rect>
<circle radius='20px' height ='22px'></circle>

Thank you .

I think if you desperately want that, read the XML with a proper parser and output it again after telling the parser not to use self-closing tags. — Joey, Jun 26 '10 at 17:37
I know this one is linked too much, but I think in this case it's appropriate: http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags — Kobi, Jun 26 '10 at 17:38
@poly: I use svg with "jquery svg" , it does not work if I write "/>" instead of "". I know it's the same. but jquery does not. @Rossel: Thanks,it's a good idea. — Abdullah, Jun 26 '10 at 17:41
so is this JavaScript, or server-side? What flavor are you using? — Kobi, Jun 26 '10 at 17:42

marg · Answer 1 · 2010-06-26T17:44:30.363

1

Like polygenelubricants noted I don't know what this would accomplish but this should be what you are looking for:

<rect[^>]*/>

and

<circle[^>]*/>

If you want to match any self-contained tag you should look at Crozins solution.

edited Jun 26 '10 at 17:44

answered Jun 26 '10 at 17:38

marg

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score 1 · Answer 2 · answered Jun 26 '10 at 17:40

1

You could use something like this #<([a-z]+)([^>]*)/># and replace with <$1$2></$1>. But regexp might differ depending on what's regexp engine you're using.

answered Jun 26 '10 at 17:40

Crozin

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score 1 · Answer 3 · answered Jun 26 '10 at 17:45

1

sed 's/<$[a-z]*$ $[^\/>]*$\/>/<\1 \2><\/\1>/'

Would do what you want (in this case)

Search pattern: <$[a-z]*$ $[^\/>]*$\/>

Replace pattern: <\1 \2><\/\1>

answered Jun 26 '10 at 17:45

Jamie Wong

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score 1 · Accepted Answer · answered Jun 26 '10 at 17:47

I don't think regex is the right tool for this job, but something like this will "work" some of the time.

    String text =
        " <rect width='10px' height ='20px'/> \n" +
        " <rect width='20px' height ='22px'/> \n" +
        " <circle radius='20px' height ='22px'/> \n" +
        " <square/> <rectangle></rectangle> \n" +
        " <foo @!(*#&^#@/> <bar (!@*&(*@!#> </whatever>";
    System.out.println(
        text.replaceAll("<([a-z]+)([^>]*)/>", "<$1$2></$1>")
    );

The above Java snippet prints:

 <rect width='10px' height ='20px'></rect> 
 <rect width='20px' height ='22px'></rect> 
 <circle radius='20px' height ='22px'></circle> 
 <square></square> <rectangle></rectangle> 
 <foo @!(*#&^#@></foo> <bar (!@*&(*@!#> </whatever>

The regex is this (see also on rubular.com):

/<([a-z]+)([^>]*)\/>/

Essentially we try to capture what we hope is a tag name in group 1, and everything else until the /> in group 2, and use these captured strings in our substitution.

References

regular-expressions.info/Grouping

What is a regular expression that find a line like this:

4 Answers4

References