find regexp in document. getelementbyid

Question

I am new to reg exp I have searched lot about pattern to find the circle brackets in the string value finally i found. But this was not working when i am getting the value from DIV

Here is the javascript code

function myText(){   
 var inputString = document.getElementById("text").innerHTML;
 var result = inputString.match(/\(+/g);
 alert(result);
 }
 myText();

HTML code

<div  id="text">
 welcome to (MotherLand)
</div>

I tried with removing .value from the inputString

I am getting the result as null in alert. I tried with removing .value from the inputString

Iam getting the error in console window Cannot read property 'match' of undefined

I am getting the result as null in alert

I want only the circle brackets not inside the value.

The output should be (

Kindly explain me what I am doing wrong.

fiddle link

Thanks Mahadevan

`innerHTML.value` will be `undefined`. Try `getElementById('text').textContent` — Phil, Jul 07 '15 at 00:47

score 2 · Answer 1 · answered Jul 07 '15 at 00:58

2

If you are trying to get the string with in the (), then you could use the following regex Pattern

http://jsfiddle.net/12auwf1s/

var inputString = document.getElementById("text").innerHTML

var result = inputString.match(/\(([^)]+)\)/);

//result[0] contains (Motherland)

//result[1] contains Motherland

answered Jul 07 '15 at 00:58

kiran

374
1
7

Hi, thanks for the output but i want only the circle brackets not inside the value. – Mr.M Jul 07 '15 at 09:04

score 1 · Answer 2 · edited May 23 '17 at 11:51

1

Here are the things I see wrong:

You need to get the value like this.

var inputString = document.getElementById("text").innerHTML;

The expression you want to find the text between "circle brackets" is:
```
var result = inputString.match(/\(([^\)]+)\)/);

\(      // Match open parenthesis
(       // Start a capture group
[^\)]+  // Match any character except a close parenthesis, repeating.
)       // End capture group
\)      // Match close parenthesis
```
result will be an array. The first position will be the entire match and subsequent positions in the array will be any capture groups from your expression. So to get the text from between the parenthesis you would access result[1].
I had trouble duplicating it in your jsFiddle because of the arabic characters. You may have to find the actual unicode values of those characters and use them in your regular expression. Insert Unicode character into JavaScript

Here's a demo without the arabic characters: http://jsfiddle.net/tvxmrLgv/7/

edited May 23 '17 at 11:51

Community

1
1

answered Jul 07 '15 at 01:01

CatDadCode

58,507
61
212
318

Hi, thanks for the output but i want only the circle brackets not inside the value. – Mr.M Jul 07 '15 at 09:04
Then simply move the capture group parenthesis outside of the `\(` and `\)`. Like this: `var result = inputString.match(/(\([^\)]+\))/);`. Demo: http://jsfiddle.net/tvxmrLgv/10/. Now it includes the parenthesis in the match. – CatDadCode Jul 07 '15 at 13:35
thank you so much for the reply. I don't want the text inside the bracket. I want only the open parenthesis not the close parenthesis. – Mr.M Jul 08 '15 at 12:38
Why would you use a regular expression to match a single open parenthesis? That's a really strange requirement, but here you go: http://jsfiddle.net/tvxmrLgv/11/ – CatDadCode Jul 08 '15 at 17:41

find regexp in document. getelementbyid

2 Answers2