Execute curl with parameters- Python 2.6.6

Question

I have the following command executed in the linux shell:

$ curl -s -K <\(echo user = "$AUTH") "${URI%/}"

where AUTH and URI are environment variables. I have tried to execute the command with python program in several ways:

1.

import os
b = os.popen('curl -s -K <(echo user = $AUTH) $URI').readlines()

2.

import subprocess
subprocess.call(
    ['curl -s -K <(echo user = $AUTH) $URI'],
    shell=True,stderr=subprocess.STDOUT
)

but I always receive an error of this kind

"sh: 1: cannot open (echo: No such file"

or

"sh: 1: Syntax error: "(" unexpected".

It seem to me there is a problem with the escaping of the special symbols. Can you help me with this one?

python is using `/bin/sh` to run your command and `/bin/sh` doesn't support process substitution. You need to manually use `/bin/bash` instead (or see if you can get python to use `/bin/bash` for `subprocess.call`). — Etan Reisner, Jul 07 '15 at 13:16
@EtanReisner thanks for the quick response! It work perfect now. — cBeTyLkaTa, Jul 07 '15 at 13:25

score 0 · Answer 1 · answered Jul 07 '15 at 13:29

0

run your command in:

cmd = "curl -s -K<conf_file> -u 'username:password' 'www.something.com'"

os.system(cmd)

answered Jul 07 '15 at 13:29

rickydj

1 Answers1