PHP - current folder / directory name

Question

how can I get the current folder/directory name in PHP?

I have two pages on my site:

/about and /help

This is my code (in about and help page):

<?php

echo dirname("index.php");

?>

I want it to return: 'about' if I am on about page. And return 'help' if I am on help page. But it returns nothing.

If I am on this path: http://www.website.com/about/index.php I want it to just return about

I tried putting: `` but it prints out the full path like: `C:\xampp\htdocs\about` - I want it to just print out `about` @Saty — TyhaiMahy, Jul 07 '15 at 13:16

score 4 · Accepted Answer · edited Feb 29 '16 at 01:09

4

getcwd();

or

dirname(__FILE__);

or (PHP5)

basename(__DIR__)

http://php.net/manual/en/function.getcwd.php

http://php.net/manual/en/function.dirname.php

edited Feb 29 '16 at 01:09

Sevle

3,109
2
19
31

answered Jul 07 '15 at 13:18

dp4solve

411
6
18

score 0 · Answer 2 · answered Jul 07 '15 at 13:19

0

echo dirname( __FILE__ );

Will print your file path

answered Jul 07 '15 at 13:19

php-coder

955
1
12
23

ash__939 · Answer 3 · 2015-07-07T13:41:45.727

If you want to get the directory where the current script resides, use dirname(__FILE__);

From your question I understand that you want to get it from the url instead. For that you can process the url (useful if URL Rewriting is done)

$full_url  = $_SERVER['REQUEST_URI'];
$url_array = explode("/", $full_url);
if(end($url_array)==='index.php' || end($url_array)==''){    
    $key = array_search('index.php', $url_array);
    if(!$key){
    //if index.php is not present and url ends with a '/'
        $key = count($url_array) - 1;
    }
    $target = (array_key_exists(($key-1), $url_array))?($key-1):$key;    
    $dir_name = $url_array[$target];
}else{
    $dir_name = end($url_array);
}
echo  $dir_name;

PHP - current folder / directory name

3 Answers3