jQuery mask input without changing value

Question

I am using masked-input-plugin but it changes value and field becomes invalid ...

in my js

$phoneInput.mask('99-99-99-999');

and later in browser console

('.phone-input-order-form').val()
"99-99-99-999"

Is there any way to get from val "999999999" while it masked ?

I am thinking to extend jQuery val but maybe you know better way? maybe without this plugin? :D

possible duplicate of [Remove literals from input mask after form submit?](http://stackoverflow.com/questions/7854651/remove-literals-from-input-mask-after-form-submit) — stevenw00, Jul 08 '15 at 10:20
seems I asked clearly - 1) or extend `val`; 2) or somehow show mask without affect to inputs value — madzohan, Jul 08 '15 at 10:23
@stevenw00 nope, It's not DRY There are many lines of code where I should add condition and put unmask or replace or whatever ... — madzohan, Jul 08 '15 at 10:28
what about a **newer** prototype so that you won't need to extend .val()? do you have to replace that .val() so many times? something like that? http://jsfiddle.net/jvr0nqz2/ — briosheje, Jul 08 '15 at 10:32
@briosheje I have took idea from this answer http://stackoverflow.com/a/5007327/3033586 — madzohan, Jul 08 '15 at 10:36
@madzohan: Not sure, I feel that it is easier to create a new prototype, but maybe it's just me. — briosheje, Jul 08 '15 at 10:40
If you change `val` things will probably stops working, because inside masked-input-plugin it also uses `val`, so it creates some kind of circular dependencies. — alan0xd7, Jul 08 '15 at 10:45

score 3 · Accepted Answer · answered Jul 08 '15 at 10:40

3

Overriding jQuery's val() function might cause unexpected issues with other scripts. Maybe try something like this:

$.fn.maskVal = function () {
    return $(this).mask();
};

answered Jul 08 '15 at 10:40

alan0xd7

score 2 · Answer 2 · answered Jul 08 '15 at 10:28

2

$('.phone-input-order-form').mask(); => "999999999"

answered Jul 08 '15 at 10:28

Evgeny Samsonov

score -1 · Answer 3 · answered Jul 08 '15 at 10:17

-1

do something like

yourstring.replace("-", "");

answered Jul 08 '15 at 10:17

jay temp

It's not DRY There are many lines of code where I should add condition and put `replace` – madzohan Jul 08 '15 at 10:20

3 Answers3