How to sort a list by last character of string

Question

I am trying to write a program that orders a list of strings based on the last character in the item.

["Tiger 6", "Shark 4", "Cyborg 8"] are how my list is imported, but I need to put them in numerical order based on the numbers at the end.

are the numbers always single digits? – Anand S Kumar Jul 09 '15 at 02:10 — Anand S Kumar, Jul 09 '15 at 02:10

Avinash Raj · Answer 1 · 2015-07-09T02:16:53.990

21

I am trying to write a program that orders a list of strings based on the last character in the item.

>>> s = ["Tiger 6", "Shark 4", "Cyborg 8"]
>>> sorted(s, key=lambda x: int(x[-1]))
['Shark 4', 'Tiger 6', 'Cyborg 8']

Try this if there are more num of digits at the last.

>>> import re
>>> sorted(s, key=lambda x: int(re.search(r'\d+$',x).group()))
['Shark 4', 'Tiger 6', 'Cyborg 8']

re.search(r'\d+$',x).group() helps to fetch the number present at the last irrespective of preceding space.

edited Jul 09 '15 at 02:16

answered Jul 09 '15 at 02:11

Avinash Raj

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Why use a lambda for the key instead of a *function*. – wwii Jul 09 '15 at 02:35
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lambda is used to create anonymous function. – Avinash Raj Jul 09 '15 at 04:26

score 5 · Answer 2 · answered Sep 04 '19 at 17:36

5

def last_letter(word):
    return word[::-1]

mylst = ["Tiger 6", "Shark 4", "Cyborg 8"]
sorted(mylst, key=last_letter)

answered Sep 04 '19 at 17:36

ronith raj

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Chandrahas Minajigi · Answer 3 · 2020-06-13T13:27:30.293

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nums = ["Tiger 6", "Shark 4", "Cyborg 8"]
slist=sorted(nums,key = lambda x:x[-1])

here nums is an list
in slist it takes list of arguments from the list nums
here lambda function takes argument from list and return it's last value(e.g. if it a first argument from nums (i.e.''Tiger 6'') and it returns 6.
sorted function return a list based on lambda function.

edited Jun 13 '20 at 13:27

answered Jun 12 '20 at 11:49

Chandrahas Minajigi

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When possible, please make an effort to provide additional explanation instead of just code. Such answers tend to be more useful as they help members of the community and especially new developers better understand the reasoning of the solution, and can help prevent the need to address follow-up questions. – Rajan Jun 12 '20 at 12:14

score 1 · Answer 4 · answered Jul 09 '15 at 02:13

If the numbers are not single digits, you can try -

>>> l = ["Tiger 6", "Shark 4", "Cyborg 8", "Temporary 12"]
>>> l.sort(key = lambda x: int(x.rsplit(' ',1)[1]))
>>> l
['Shark 4', 'Tiger 6', 'Cyborg 8', 'Temporary 12']

str.rsplit(s, n) function starts splitting the string at the end towards start of the string and stops after n splits. In the above case, it only splits the string once, at a space.

How to sort a list by last character of string

4 Answers4

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