You are storing pointers that point at the internals of temporary std::wstring
objects. When those objects are destroyed on each loop iteration, your array is left with danging pointers. You need to dynamically allocate the individual strings instead, eg:
std::cin >> count
LPWSTR *lpwstrArray = new LPWSTR[count];
for (int i = 0; i < count; i++)
{
// some logic to create different wstring on each iteration
std::wstring tempWString = L"somerandomstuff";
LPWSTR str = new WCHAR[tempWString.length()+1];
const wchar_t *p = tempWString.c_str();
std::copy(p, p+tempWString.length(), str);
lpwstrArray[i] = str;
}
// use lpwstrArray as needed...
// don't forget to free the memory when you are done using it...
for (int i = 0; i < count; i++)
delete[] lpwstrArray[i];
delete[] lpwstrArray;
Depending on what you are really trying to accomplish, something more like the following would be safer, at least if you just need read-only access to the strings (which you likely do, as the C
in LPCWSTR
stands for const
, so the user of the array is not going to be modifying them):
std::cin >> count
std::vector<std::wstring> wstrArray(count);
for (int i = 0; i < count; i++)
{
// some logic to create different wstring on each iteration
wstrArray[i] = L"somerandomstuff";
}
std::vector<LPWSTR> lpwstrArray(count);
for (int i = 0; i < count; i++)
lpwstrArray[i] = const_cast<wchar_t*>(wstrArray[i].c_str());
// use lpwstrArray as needed. if you need to pass it where an
// LPWSTR* is expected, you can use &lpwstrArray[0] for that...
// lpwstrArray and wstrArray will be freed automatically
// when they go out of scope...