python what does "%ds" mean in format?

Question

What does "%ds" in following codes mean?

theline = 'aaaaaeeebbbbbbbbccccccccddd'
baseformat = "5s 3x 8s 8s"
numremain = len(theline) - struct.calcsize(baseformat)
format = "%s %ds" % (baseformat, numremain)
s1, s2, s3, s4= struct.unpack(format, theline)

This might help you: http://stackoverflow.com/questions/4288973/s-and-d-python — Nomesh DeSilva, Jul 10 '15 at 03:39
I know the meaning of "%s" or "%d", but I can not understand the usage of "%ds" — Lancert9, Jul 10 '15 at 03:41

score 7 · Answer 1 · answered Jul 10 '15 at 03:44

7

The '%ds' is not a format specifier. It's '%d' followed by 's':

>>> "%ds" % 6
6s

answered Jul 10 '15 at 03:44

dlask

8,776
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score 1 · Answer 2 · answered Jul 10 '15 at 03:56

1

"%ds" here is a format specifier plus a single string "s". For the codes above, it specifies the length of "remain string".

answered Jul 10 '15 at 03:56

Lancert9

41
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python what does "%ds" mean in format?

2 Answers2