How do i access the private data of an object which is passed by reference to operator= function?

Question

I wonder how I am able to access the private data of an object which is passed by reference or value? this code works. Why? i need some explanations.

class test_t {
    int data;
public:
    test_t(int val = 1): data(val){}
    test_t& operator=(const test_t &);
};

test_t& test_t::operator=(const test_t & o){
    this->data = o.data;
    return *this;
}

See http://stackoverflow.com/questions/6921185/why-do-objects-of-the-same-class-have-access-to-each-others-private-data — Christian Hackl, Jul 12 '15 at 12:44

Aaron McDaid · Accepted Answer · 2015-07-12T12:30:39.900

6

private means that all instances of the test_t class can see each other's private data.

If C++ was to be stricter, and to limit private access to methods within the same instance, it would be effectively saying that the type of *this is "more powerful" than the type of your o reference.

The type of *this is the same (†) as the type of o, i.e. test_t &, and therefore o can do anything that *this can do.

(†) The same type, apart from the addition of const, but that's not important here.

edited Jul 12 '15 at 12:30

answered Jul 12 '15 at 12:22

Aaron McDaid

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To put it semantically, `private` means that it's part of the implementation of the class and can only be accessed by the implementation of the class. – David Schwartz Jul 12 '15 at 12:26

How do i access the private data of an object which is passed by reference to operator= function?

1 Answers1