How can I get the name of functions dynamically

Question

I can put those about to be executed functions in to functions_results.

I get print out the results, but I couldn't get the functions itself name.

For example,

functions_results = [
    schedules(),
    schedules("2014-06-01", "2015-03-01"),
]

list_of_functions_heads = [x for x in functions_results]
for i in list_of_functions_heads:
    # this is what I want to get
    # print(i.FUNCTION_NAME) # 'schedules()'

    print(i.head())

name not work in my case

print(i.name)

    (type(self).__name__, name))
AttributeError: 'DataFrame' object has no attribute '__name__'

You already called the `schedules` function, so you cannot get the name of the function object.. What does `schedules()` return at all to have a `.head()` method? — Martijn Pieters, Jul 15 '15 at 07:21

score 1 · Answer 1 · answered Jul 15 '15 at 07:21

1

You can access this through function.__name__.

answered Jul 15 '15 at 07:21

James

1,198
8
14

__name__ not work in my case, pls see my updatem thanks – user3675188 Jul 15 '15 at 07:41
This is because `i` is not a function in your code. `i` is `schedules()` or `schedules("2014-06-01", "2015-03-01")`, which going by your Error message, seem to be `DataFrame` objects. You need to make sure your object is actually a function if you want to use `__name__`. – James Jul 15 '15 at 18:01

Mazdak · Answer 2 · 2015-07-15T07:34:16.857

You can use __name__ attribute to get your function name :

Example :

>>> def my_func():
...   print 'my_func'
... 
>>> my_func.__name__
'my_func'

Read more about python modules https://docs.python.org/2/tutorial/modules.html#modules

Also note that since you have called your function within functions_results :

functions_results = [
    schedules(),
              ^ #here you called the function 
    schedules("2014-06-01", "2015-03-01"),
]

So you can not get its name in your loop. for example if in preceding example we want to get the name of function after call python will raise an AttributeError:

>>> my_func().__name__
my_func
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'NoneType' object has no attribute '__name__'
>>>

So for getting ride of this problem you need to put the function without calling it in your list :

functions_results = [
    schedules, 
    schedules("2014-06-01", "2015-03-01"),
]

Also note that you can not do it again for second function call :

schedules("2014-06-01", "2015-03-01")

and for getting ride of this problem too you can use hasattr(obj, '__call__') method (and callable in python3 )to check if i was a function type then get its name :

for i in list_of_functions_heads:
      if hasattr(i, '__call__'):
           print i.__name__

@user3675188 Did you have read my answer completely?I explained that you shouldn't call your function and use `hasattr` in your loop — Mazdak, Jul 15 '15 at 07:43
yes, i tried, but `schedules("2014-06-01", "2015-03-01")` how could I avoid it be called in my method, thanks — user3675188, Jul 15 '15 at 07:47

score 0 · Answer 3 · answered Jul 15 '15 at 07:22

0

access this through function.__name__.

>>> def a():
...     pass
... 
>>> a.__name__
'a'
>>>

answered Jul 15 '15 at 07:22

sinhayash

2,693
4
19
51

How can I get the name of functions dynamically

name not work in my case

3 Answers3