how to start a process under Windows with call?

Question

I have the following code which works under Linux :

ProcessStartInfo startInfo = new ProcessStartInfo(); 

// Set in the process the executable and arguments
startInfo.FileName = "ps";
startInfo.Arguments = "a";

Process proc = Process.Start(startInfo);

proc.WaitForExit();

return proc.ExitCode;

However when I try using the process under Windows for a simple commands :

ProcessStartInfo startInfo = new ProcessStartInfo(); 

// Set in the process the executable and arguments
startInfo.FileName = "call";
startInfo.Arguments = "gpedit.msc";

Process proc = Process.Start(startInfo);

proc.WaitForExit();

return proc.ExitCode;

It doesn't work (I know running thins command in cmd.exe works fine).

I get : Win32Exception was unhandled.

I also read this tutorial over again : How do I start a process from C#?

I used process a lot under Linux but I cannot see what I do wrong in Windows.

Is 'call' in the same directory as the executable of your code? — Bsa0, Jul 15 '15 at 14:07
`CALL` is a batch command, only available from the command line. You should be able to just specify `gpedit.msc` as the “file name” without specifying any argument to launch the management tool. — poke, Jul 15 '15 at 14:09
gpedit.msc is the process you are trying to run - so that should be the FileName — PaulF, Jul 15 '15 at 14:11
1-)Call is indeed in the same directory 2-) I'm gonna try not having the call and report if it works — Cher, Jul 15 '15 at 14:26

score 2 · Accepted Answer · edited Jul 15 '15 at 15:03

2

CALL is a batch command, only available from the command line (poke)

I instead use start and it works fine.

edited Jul 15 '15 at 15:03

poke

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answered Jul 15 '15 at 14:49

Cher

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score 1 · Answer 2 · edited Jul 15 '15 at 15:03

1

Two Options:

Call the MMC executable with GPEDIT parameter

startInfo.FileName = "MMC.EXE";
startInfo.Arguments = "GPEDIT.MSC";

Or call GPEDIT.MSC with no parameters

startInfo.FileName = "GPEDIT.MSC";

edited Jul 15 '15 at 15:03

poke

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answered Jul 15 '15 at 14:25

Mike

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how to start a process under Windows with call?

2 Answers2