make a function callback outside of $.ajax?

Asked Jul 16 '15 at 06:40

Active Jul 16 '15 at 06:40

Viewed 29 times

function ajax(){
    $.ajax({
    ..
    ..
    success:function(response){

    }
    });
    }

$('button').click(function(){
ajax() <-- if success do after this

});

$('.button2').click(function(){
ajax() <-- if success do after this

});

I have few element that need to run a ajax function but how can I do a callback? since ajax is async I can't simply run something after the function.

asked Jul 16 '15 at 06:40

Lee shienlong

Umm, I am a little confused. So i can see that when you click the button, you make an ajax call. Do you want to run something once the ajax call is done? – Pratik Jul 16 '15 at 06:43
You can pass anything ( e.g. functions ) to ajax and then just simple call it in success callback. – kuba Jul 16 '15 at 06:43
@Pratik yes. but I want to make my $.ajax as a function. – Lee shienlong Jul 16 '15 at 06:48
@kuba my success callback will have 5 condition if i have 5 button? that's redundant. – Lee shienlong Jul 16 '15 at 06:48
Is that what you want? http://jsfiddle.net/g3zcd2yx/ – Alex Jul 16 '15 at 06:51
This is how you can pull your code out into a separate callback function and pass the parameters around: http://jsfiddle.net/abhitalks/k57bnn0a/1/ – Abhitalks Jul 16 '15 at 07:06

make a function callback outside of $.ajax?

0 Answers0