First of all thanks for answering and helping out...
Now i was making a program to let the user enter any number... and then use the program to point out the total number of 4's in the the number entered and i have now encountered a problem..
This is my first post here so please excuse me if i make any mistakes..
The Code
int main()
{
int T,i,j,l;
char N,p[10];
cin>>T;
while(T--) //The number of times a user can enter a new number
{
cout<<"\nEnter Numbers\n";
l=0;i=0;
do
{
N=getch(); //getch is used so that the enter key need not be pressed and the
//number looks like a whole and also so the each number is
//individually stored
p[i]=N; //here the number entered is stored in p
cout<<N; //to display the number obviously
l++;i++;
}while(N!=' '); //Now here between '' something has to be present so that the loop
//terminates as soon as the enter key is pressed right now as soon
//as the spacebar is hit the loop will terminate.
cout<<"\n";
j=0;
for(i=0;i<l;i++) //using l so that the loop runs accordingly
{
if(p[i]=='4')
{
j++; //for couting the number of 4's
}
cout<<p[i]<<"\n"; //wont be needing in the final program but here cout is just
// to check the output
}
cout<<"\n THERE ARE "<<j<<" FOURS\n";
}
}
Please not that i already have a solution for my program so please DO NOT provide a different code using some different logic... i really need this very same program to work.i know that this program can be made to work using string length but here i want the loop to terminate after the enter key is pressed.