How Can I Get The indexpath and row in XCODE 5

Question

I have an app that used to work before I upgraded to XCODE 5. I needed to find the row that was selected for a structure I was displaying which has over 100 rows so obviously can be scrolled on the display. The code that used to work is:

NSIndexPath *indexPath = [self.mainTableView indexPathForCell:myCell];
NSInteger row = [indexPath row];

Now, regardless of the row selected, the value of row is always 0. Anyone have any suggestions for me? Thanks.

I remember that working in XCode 6 at least... you may have to provide more context... — User, Jul 19 '15 at 23:42
Try indexPath.row? Probably doesn't do any difference but heck :) — ErickES7, Jul 20 '15 at 02:05
Or check to see if self.table is still valid, as well as myCell — ErickES7, Jul 20 '15 at 02:05

score 0 · Answer 1 · answered Jul 22 '15 at 02:12

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This worked for me...

CGPoint pos = [pressedButton convertPoint:CGPointZero toView:self.mainTableView];
NSIndexPath *indexPath = [self.mainTableView indexPathForRowAtPoint:pos];
NSInteger row = [indexPath row];

answered Jul 22 '15 at 02:12

Rick

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score 0 · Answer 2 · edited May 23 '17 at 12:29

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Remember that in Objective-C, you can always send a message nil, and methods that return something (i.e., not void) will return either nil(for an object) or 0 (for a value) when sent to nil (for structs, it is more complicated; read this).

So make sure that:

self.mainTableView is not nil
indexPath is not nil

edited May 23 '17 at 12:29

Community

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answered Jul 22 '15 at 02:23

Nicolas Miari

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How Can I Get The indexpath and row in XCODE 5

2 Answers2