Implementing a Type Defined in a Template Argument

Question

This code runs on Visual Studio 2013 but not on gcc 4.9.2:

template <typename T>
void foo(){
    T::value_type bar('a');

    cout << bar << endl;
}

int main() {
    foo<string>();

    return 0;
}

It seems that Visual Studio 2013 deduces type to allow me to implement types defined in template arguments whereas gcc 4.9.2 does not.

Is there a workaround for this that would allow this behavior in gcc?

what is the error you are getting, this will help – Vinay Shukla Jul 20 '15 at 11:06 — Vinay Shukla, Jul 20 '15 at 11:06

score 2 · Accepted Answer · edited May 23 '17 at 12:14

2

You need to tell the compiler that T::value_type names a type so that it knows how to parse the declaration.

typename T::value_type bar('a');

See this question for more details on where and why you need to do this.

edited May 23 '17 at 12:14

Community

answered Jul 20 '15 at 11:06

TartanLlama

1 Answers1