Using values from PHP in JavaScript

Question

I would like to use a value from PHP in JavaScript, but it's not working. I fetch data from a database and store it in a PHP variable and for conditional formatting. I need to also use the data in JavaScript for validation.

The value required by me is $date = date('Y-m-d'); If I pass the value by json Encode the alert function is not working...

$(document).ready(function()
{
alert("Hi");
var array = php print(json_encode($date)); 
});

Whereas if I just alert the function without...

var array = php print(json_encode($date)); ;

...it works fine.

<script type="text/javascript" src="assests/js/jquery-1.10.2.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
alert("Hi");
var array = '<?php print(json_encode($date)); ?>';
});
</script>
</head>
<body>
<form action="majorprocess.php">
<?php
$dbconn = mysql_connect('localhost', 'root','' );
if(!$dbconn)
{
die(mysql_error());
}
else
{
$date = date('Y-m-d');

Try using `` then you can get it by using `document.getElementById`. Store your data in hidden field so that you can use them with js — Hearner, Jul 22 '15 at 13:22
Warning: You are using the `mysql_xxx()` functions for your database access. These functions are deprecated, and are being removed in the next version of the language. You are strongly advised to migrate your code to use the other methods available -- either the `mysqli_xxx()` functions, or the PDO library. See also: [Why shouldn't I use the mysql functions in PHP?](http://stackoverflow.com/questions/12859942/why-shouldnt-i-use-mysql-functions-in-php) — Simba, Jul 22 '15 at 13:48

score 1 · Answer 1 · answered Jul 22 '15 at 13:24

1

<script type="text/javascript" src="assests/js/jquery-1.10.2.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
    alert("<?php echo json_encode(date('Y-m-d')); ?>");
});
</script>

answered Jul 22 '15 at 13:24

tesst

149
1
11

score 0 · Answer 2 · answered Jul 22 '15 at 13:25

0

What is the resulting HTML? There could be a PHP error outputting instead of valid javascript.

Try putting the PHP section at the top maybe?

When asking a question it is always best to post any outputs you are getting so people can help.

answered Jul 22 '15 at 13:25

Christian

1,557
11
16

score 0 · Answer 3 · answered Jul 22 '15 at 13:39

try this one

     </head>
      <body>
      <form action="majorprocess.php">
      <?php
       $dbconn = mysql_connect('localhost', 'root','' );
        if(!$dbconn)
        {
         die(mysql_error());
        }
         else
            {
             $date = date('Y-m-d');
            }
        ?>
        <script type="text/javascript" src="assests/js/jquery-1.10.2.js"></script>
        <script type="text/javascript">
         $(document).ready(function(){
          var array = '<?php print(json_encode($date)); ?>';
           alert(array);
           });
          </script>

score 0 · Answer 4 · answered Jul 22 '15 at 13:43

You are using the PHP $date variable before setting its value. Make sure to move the php block before you try to output the date:

<?php
$dbconn = mysql_connect('localhost', 'root','' );
if(!$dbconn)
{
    die(mysql_error());
}
else
{
    $date = date('Y-m-d');
}
?>
<script type="text/javascript" src="assests/js/jquery-1.10.2.js"></script>
<script type="text/javascript">
$(document).ready(function()
{
    alert("<?php echo json_encode($date) ?>");
});
</script>

Using values from PHP in JavaScript

4 Answers4