How to create a random 4 digit number and store it as a variable

Question

I am working on a guess-the-4-digit-number game in python 2.7.10. But I cannot find how to randomly make a 4 digit number, and store it as a variable. The digit has to be somewhere between 1111 and 9999 The hard part is, that I want to store it as a variable, and not print it out for the player to see.

If you want to, I'll post the code when I'm finished.

The code is finally here!

import random
number = random.randint(1111,9999)
tryagain = 'yes'
print ('hello! ')
print ('------------------------------------------------------------- ')
print ('Try and guess the 4 digit number in the least number of tries ')
print ('------------------------------------------------------------- ')
while tryagain == 'yes':
    lowoutput = None
    highoutput = None
    guess = None
    guess = input('Guess: ')
    if guess == number:
        print ('Correct! ')
        correctoutput str(raw_input(Enter 'exit' to exit: "))
        If correctoutput == 'exit':
            print 'Goodbye'
            exit()
        else:
            print 'invalid input'
    elif guess > number:
        print 'Your answer is too high'
        highoutput = str(raw_input("Try again? 'Y'/'N'))
        if highoutput == 'n':
            tryagain = 'n'
        elif highoutput == 'y'
            try again = 'yes'
        else:
            print 'invalid input'
    else:
        print 'Your answer is too low' 
        lowoutput = str(raw_input("Try again 'y'/'n'"))
        if lowoutput == 'n':
            try again = 'n'
        elif lowoutput == 'y'
            tryagain = 'yes'
        else:
            print 'invalid input'
print 'too bad, the right answer was: '
print (number)
exit()

This should work. There might be some mistakes cos I wrote this on my tablet. All improvements would be accepted

Here - https://wiki.python.org/moin/BeginnersGuide/NonProgrammers - This should get you started. — Anand S Kumar, Jul 23 '15 at 15:18
I know the basic programing and how to get the random number, I just can't store it in a variable — Tech Heck, Jul 23 '15 at 15:26
I am trying to be as humble as possible when I say this, But when you ask - *how do I store a return value of a function in a variable* - You do not know basic programming - you should really give the link a try. — Anand S Kumar, Jul 23 '15 at 15:29
Will this work Import random r = random.randint(1111,9999) will the variable r be the number? — Tech Heck, Jul 23 '15 at 15:35
Yea sure, you can update in the question, for others to see. — Anand S Kumar, Jul 23 '15 at 15:46
4 spaces for each code line or just hightlight the complete code and click on the `code` icon on the top. — Anand S Kumar, Jul 23 '15 at 15:49

score 5 · Accepted Answer · answered Jul 23 '15 at 14:13

5

try with

import random
r = random.randint(1111,9999)
print "%04d" % r

or

print '{0:04d}'.format(r)

answered Jul 23 '15 at 14:13

Pynchia

10,996
5
34
43

What about numbers `1000` to `1110`? – poke Jul 23 '15 at 14:32
I don't want to print it, I want it to be secret – Tech Heck Jul 23 '15 at 15:09
@poke because the OP asked for 1111 to 9999. but you could even do 0 to 9999 and it'll be a 4-digit random due to the format string. – Jason Wiener Jun 08 '17 at 00:21

How to create a random 4 digit number and store it as a variable

1 Answers1