Scala - How to get a wrapped method's name?

Asked Jul 23 '15 at 16:11

Active Jul 23 '15 at 17:09

Viewed 32 times

I have the following wrapper:

def ProtectedAction[T](f: => T)(implicit user: User): T = {
    if(isAuthorized()) f
    else { 
        Logger.warn(user.login + "Had access denied to" + methodsName)
        throw new NotAuthorizedException("You do not have permission to execute this operation.")
    }
}

I'd like to get the simpleName of the method wich is being held by f. How can I do that?

asked Jul 23 '15 at 16:11

RafaelTSCS

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`f` doesn't necessarily have a name, it could be anonymous – Ryan Jul 23 '15 at 16:39
Right.. but what if it does? – RafaelTSCS Jul 23 '15 at 16:39
`f` will never have a name, see the linked duplicate – Michael Zajac Jul 23 '15 at 17:13
got it. So if I really need to know its name, I should somehow pass it forward . – RafaelTSCS Jul 23 '15 at 17:16

Scala - How to get a wrapped method's name?

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