import and call a function with es6

Question

Previously:

var debug = require('debug')('http')
  , http = require('http')
  , name = 'My App';

With es6, how can I import and invoke right away like the first line?

import debug from 'debug'();

is a no no?

score 49 · Accepted Answer · answered Jul 23 '15 at 23:24

49

You'll need two lines:

import debugModule from 'debug';
const debug = debugModule('http');

The import syntax is a declarative import syntax, it does not execute any functions.

answered Jul 23 '15 at 23:24

loganfsmyth

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The problem is that sometimes you need to call the function before any other import statements. `import` does not allow the execution of other statements before all `import` statements are declared. – user2078023 Apr 10 '19 at 11:32
@user2078023 In that case it may be best to move the whole import-and-call into a separate module, which you can import when you need both to happen. – JW. Apr 25 '23 at 02:02

score 4 · Answer 2 · answered Jul 23 '15 at 23:26

is a no no?

Correct. Keep in mind that the import statement is analogous to more than a simple require() statement -- it also creates a binding of the "loaded" module to a local variable.

That is,

import debug from 'debug'();

...is more close in behavior/semantics to

var debug = require('debug');

...than it is to simply

require('debug');

Analogies to commonjs-style module loaders will obviously break down at some point, but at the end of the day it's a "no no" due to the plain and simple fact that import debug from 'debug' doesn't actually resolve to anything that you can invoke (or otherwise reference).

score -21 · Answer 3 · answered Jul 23 '15 at 23:20

-21

import http from "debug"; // not sure if this is the desired effect

answered Jul 23 '15 at 23:20

Vidul

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Be sure, this doesn't have a desired effect – maxkoryukov Mar 29 '17 at 23:53

import and call a function with es6

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